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Lelu [443]
3 years ago
7

Can anyone help me integrate :

Mathematics
1 answer:
worty [1.4K]3 years ago
3 0
Rewrite the second factor in the numerator as

2x^2+6x+1=2(x+2)^2-2(x+2)-3

Then in the entire integrand, set x+2=\sqrt3\sec t, so that \mathrm dx=\sqrt3\sec t\tan t\,\mathrm dt. The integral is then equivalent to

\displaystyle\int\frac{(\sqrt3\sec t-2)(6\sec^2t-2\sqrt3\sec t-3)}{\sqrt{(\sqrt3\sec t)^2-3}}(\sqrt3\sec t)\,\mathrm dt
=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\sqrt{\sec^2t-1}}\,\mathrm dt
=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\sqrt{\tan^2t}}\,\mathrm dt
=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{|\tan t|}\,\mathrm dt

Note that by letting x+2=\sqrt3\sec t, we are enforcing an invertible substitution which would make it so that t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3} requires 0\le t or \dfrac\pi2. However, \tan t is positive over this first interval and negative over the second, so we can't ignore the absolute value.

So let's just assume the integral is being taken over a domain on which \tan t>0 so that |\tan t|=\tan t. This allows us to write

=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\tan t}\,\mathrm dt
=\displaystyle\int(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\csc t\,\mathrm dt

We can show pretty easily that

\displaystyle\int\csc t\,\mathrm dt=-\ln|\csc t+\cot t|+C
\displaystyle\int\sec t\csc t\,\mathrm dt=-\ln|\csc2t+\cot2t|+C
\displaystyle\int\sec^2t\csc t\,\mathrm dt=\sec t-\ln|\csc t+\cot t|+C
\displaystyle\int\sec^3t\csc t\,\mathrm dt=\frac12\sec^2t+\ln|\tan t|+C

which means the integral above becomes

=3\sqrt3\sec^2t+6\sqrt3\ln|\tan t|-18\sec t+18\ln|\csc t+\cot t|-\sqrt3\ln|\csc2t+\cot2t|-6\ln|\csc t+\cot t|+C
=3\sqrt3\sec^2t-18\sec t+6\sqrt3\ln|\tan t|+12\ln|\csc t+\cot t|-\sqrt3\ln|\csc2t+\cot2t|+C

Back-substituting to get this in terms of x is a bit of a nightmare, but you'll find that, since t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3}, we get

\sec t=\dfrac{x+2}{\sqrt3}
\sec^2t=\dfrac{(x+2)^2}3
\tan t=\sqrt{\dfrac{x^2+4x+1}3}
\cot t=\sqrt{\dfrac3{x^2+4x+1}}
\csc t=\dfrac{x+2}{\sqrt{x^2+4x+1}}
\csc2t=\dfrac{(x+2)^2}{2\sqrt3\sqrt{x^2+4x+1}}

etc.
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3 years ago
B. If some amount of water contains 1400 oxygen atoms, how many hydrogen atoms does it contain?
Genrish500 [490]

Answer:

B: 2800 hydrogen atoms

C: 6760 hydrogen atoms

D: y=amount of oxygen atoms*2

Step-by-step explanation:

B: We know the formula for water is H2O. SO that means that there is 2 hydrogen atoms and 1 oxygen atom. So there is 2 times the amount of hydrogen atoms so we can do 1400*2=2800, So there is 2800 hydrogen atoms in the water.

C: Same thing as B. 3380*2=6760

D: y=amount of oxygen atoms*2. Because there is one oxygen atom and two hydrogen atoms so 1*2=2.

5 0
3 years ago
Assume the rate of inflation is ​8% per year for the next 2 years. What will be the cost of goods 2 years from​ now, adjusted fo
Paha777 [63]
<h3>Answer: $326.59</h3>

==============================================

Work Shown:

F = future value

P = present value = 280

r = rate of inflation in decimal form = 0.08

t = elapsed time in years = 2

---------

F = P*(1+r)^t

F = 280*(1+0.08)^2

F = 326.592

F = 326.59

8 0
3 years ago
How do I write this in slope intercept form: (-3,-4) and (4,-3)
DENIUS [597]
Slope intercept form is y = mx + b

Pick one of the coordinates, I’ll use (-3,-4) as the example.

Coordinates are just numbers plugged in for (x,y).

This means -3 would be your x and -4 would be your y.

So plug these numbers into the equation and you get -4 = m(-3) + b.

M is slope and to find slope, you need to do (y2-y1) / (x2-x1).

In other words, it would be (-3 - -4) / (4 - -3) = 1/7 which is your slope (m).

Now plug that in for m to get the b variable.

-4 = 1/7(-3) + b.

B = -3.57

Your answer is y = 1/7x -3.57
7 0
3 years ago
Translate ƒ(x) = |x| so that it's translated up by 5 units and vertically stretched by a factor of 3. What's the new function g(
zavuch27 [327]

Given:

The parent absolute function is

f(x)=|x|

To find:

The new function if the parent function is translated up by 5 units and vertically stretched by a factor of 3.

Solution:

The translation is defined as

g(x)=kf(x+a)+b                .... (1)

Where, k is stretch factor, a is horizontal shift and b is vertical shift.

If 0<k<1, then the graph compressed vertically by factor k and if k>1, then the graph stretch vertically by factor k.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

Parent function is translated up by 5 units. So, b=5

It is vertically stretched by a factor of 3. So, k=3.

There is no horizontal shift. So, a=0.

Now, putting k=3, a=0 and b=5 in (1), we get

g(x)=3f(x+0)+5

g(x)=3f(x)+5

g(x)=3|x|+5       [\because f(x)=|x|]

Therefore, the correct option is D.

5 0
3 years ago
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