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3 years ago

Homework help!!

2 answers:

8 0

Given total budget of the party = $45,000
reception hall charges for clean up =$60
extra fee per person =$30
Find out the number of people are invited.
To proof
let us assume that the number of people are invited in the reception are be x.
Given in the question the $60 be the clean up charge and $30 be fee per person.
than equation become
⇒ 60 +30x = 4500
30x = 4500-60
30x = 4440
x = 148
The number of people are invited in the reception are 148
Hence proved

weqwewe [10]3 years ago

7 0

Answer:

124 people

Step-by-step explanation:

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Which ordered pair in the form (a,b) is a solution of the equation?

kondor19780726 [428]

Answer:

A. (6,0)

Step-by-step explanation:

4a- 5b = 24

Check each point to see if its is true

A. (6,0)

4(6) - 5(0) = 24

24 = 24

true

B. (-5, -2)

4(-5) -5(-2)= 24

-20 +10 = 24

-10 =24

False

C. (0,6)

4(0) -5(6) =24

-30 =24

False

D. (-2, -5)

4(-2) -5(-5)=24

-8+25=24

18=24

False

3 0

3 years ago

A cylindrical soup can has a diameter of 3.6 in. and is 6.4 in. tall. Find the volume of the can.

arsen [322]

<h2>⚘Your Answer:------</h2>

<h3>Given Information:</h3>

Diameter of can:- 3.6 cm
Height of can:- 6.4 cm

Volume of the Can.

<h3>Solution:</h3>

Radius = (Diameter/2)

ㅤㅤㅤㅤ3.6 cm/2

ㅤㅤㅤㅤ1.8 cm

So, Radius of the soup can is 1.8 cm.

Volume øf cylinder = Volume øf can

Volume of cylinder = π r²h

(π = 22/7)

(r = radius = 1.8 cm)

(h = height = 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7×(1.8 cm)²× 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7× 3.24 cm² × 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7 × 20.736 cm³

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= (456.192/7) cm³

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 65.17 cm³

So, the Volume of the soup can is 65.17 cm³

ㅤㅤㅤㅤㅤㅤㅤㅤ⚘Thank You

7 0

2 years ago

HELP PLS !! WORTH 62 PTS !!!

kupik [55]

I believe it would be 12/18 so that would be 2/3 and 0.6 in decimal form

4 0

2 years ago

Read 2 more answers

For what values does c have no solutions?

defon

Solve for c :

x⁴ + cx² + 100 = 0

cx² = -(x⁴ + 100)

c = - (x⁴ + 100)/x²

If x = 0, the right side is undefined and c would have no solution.

3 0

2 years ago

the question is in the picture below, if you could show all your work so i can see how to do it, that would be appreciated.

ki77a [65]

m∠R = 27.03°

Solution:

Given In ΔQRP, p = 28 km, q = 17 km, r = 15 km

To find the measure of angle R:

Law of cosine formula for ΔQRP:

$r^{2}=p^{2}+q^{2}-2 pq \cos R$

Substitute the given values in the above formula.

$(15)^{2}=(28)^{2}+(17)^{2}-2 (28)(17) \cos R$

$225=784+289-952 \cos R$

$225=1073-952 \cos R$

Switch the given equation.

$1073-952 \cos R=225$

Subtract 1073 from both side of the equation.

$-952 \cos R=-848$

Divide by –952 on both sides.

$$ \cos R=\frac{106}{119}$

$$ R=\cos^{-1} \left(\frac{106}{119}\right)$

$R=27.03^\circ$

Hence m∠R = 27.03°.

7 0

3 years ago