Question

Who knows how to answer this. It's Dividing complex numbers.​

Answer 1

Answer:

$\large\boxed{1+i}$

Step-by-step explanation:

$\frac{4+2i }{3-i}$

Factor the numerator

$\frac{2(2+i) }{3-i}$

Multiply both numerator and denominator by the conjugate of the denominator.

$\frac{2(2+i) }{3-i} \cdot \frac{3+i }{3+i} = \frac{2(2+i)(3+i) }{9-i^2}$

Once $i^2=-1$

$\frac{2(2+i)(3+i) }{10}$

Solving the numerator

$2(2+i)(3+i) = 2(6+2i+3i+i^2) = 2(6+5i-1)=2(5+5i)$

$\frac{2(5+5i)}{2 \cdot 5} =\frac{5+5i}{5}=\boxed{1+i}$

Answer 2

Answer:

answe is 1+i

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