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3 years ago

Slope= -1; y-intercept = 8

Mathematics

2 answers:

boyakko [2]3 years ago

6 0

Answer:

you need to plug the slope and y-intercept to form an equation

y = -1x+8

kotykmax [81]3 years ago

4 0

Answer:

y=-1x+8

Step-by-step explanation:

idk what to do here

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Please solve this for me

FrozenT [24]

Answer:

Brainilest!

Step-by-step explanation:

V = (15 x 28) / 3

V = 140 in ^3

4 0

4 years ago

Read 2 more answers

The graph of

ratelena [41]

Answer:

Positive and negative intervals on a graph

Step-by-step explanation:

The positive regions of a function are those intervals where the function is above the x-axis. It is where the y-values are positive (not zero). The negative regions of a function are those intervals where the function is below the x-axis. It is where the y-values are negative (not zero). hope this helps you :)

3 0

3 years ago

Read 2 more answers

Someone please help me!

Vlad1618 [11]

Answer:

A. $x \leq -16$

B. b > 11

C. $c \leq -13$

D. $x \geq -9$

Step-by-step explanation:

<u>Given the following algebraic expression;</u>

A. $\frac {3x}{4} \leq 12$

We would simplify the equation by multiplying all through by 4;

$4 * \frac {-3x}{4} \leq 12 * 4$

$-3x \leq 48$

Divide both sides by -3;

$x \leq -16$

B. 5b - 28 > 27

Rearranging the equation, we have;

5b > 27 + 28

5b > 55

Divide both sides by 5

b > 11

C. $13c \leq -169$

Divide both sides by 13

$c \leq -13$

D. $3x - 7 \geq 4x + 2$

Collecting like terms, we have;

$3x - 4x \geq 2 + 7$

$-x \geq 9$

Divide both sides by -1

$x \geq -9$

8 0

3 years ago

The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of

ser-zykov [4K]

Answer:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$ , for $r_{1} = 0$

Step-by-step explanation:

The general form of quintic-order polynomial is:

$p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f$

According to the statement of the problem, the polynomial has the following roots:

$p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)$

Then, some algebraic handling is done to expand the polynomial:

$p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)$

$p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x$

If $r_{1} = 0$ , then:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$

5 0

3 years ago

Write the recursive formula then determine the next term of 3,10,24,52

Schach [20]

Answer:

f[1] = 3
f[n] = 2·f[n-1] +4
108

Step-by-step explanation:

We observe that first differences of the given numbers are ...

10 -3 = 7

24 -10 = 14

52 -24 = 28

That is, each difference is 2× the previous one. This suggests an exponential relation that has a base of 2.

We notice that doubling a term doesn't give the next term, but gives a value that is 4 less than the next term. So, we can get the next term by doubling the previous one and adding 4.

Then our recursive relation is ...

f[1] = 3 . . . . the first term

f[n] = 2×f[n-1] +4 . . . . double the previous term and add 4

The next term is 2·52 +4 = 108.

7 0

4 years ago