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Andreyy89
3 years ago
6

A line that intersects a circle at two points is a(n)______ of the circle.

Mathematics
1 answer:
Brut [27]3 years ago
8 0

Answer:

secant

Step-by-step explanation:

A secant is a line that intersects a circle in exactly two points.

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One serving of granola provides 4% of the protein you need daily. You must get the remaining 48 grams from other sources. How ma
Anna35 [415]
You will need 46.08 grams.

48 • 0.04 (4%) = 1.92
multiply 48 by 0.04 to find what 4% of 48g is
48 - 1.92 = 46.08
then subtract the 4% to get the rest amount
6 0
3 years ago
I’ll send a picture of problem and graph I don’t know how to write it out on here.
JulsSmile [24]

• Given the table of values, you can identify these points:

(0,4),(1,8),(2,12),(3,16),(5,24),(6,28),(7,32)

If you plot them on a Coordinate Plane, you get:

As you can observe, it is a Linear Function.

• The equation of a line in Slope-Intercept Form is:

y=mx+b

Where "m" is the slope of the line and "b" is the y-intercept.

In this case, you can identify in the graph that:

b=4

Therefore, you can substitute that value and the coordinates of one of the points on the line, into this equation:

y=mx+b

And then solve for "m", in order to find the slope of the line.

Using this point:

(1,8)

You get:

\begin{gathered} 8=m(1)+4 \\ 8-4=m \\ m=4 \end{gathered}

Therefore, the equation for the data in Slope-Intercept Form is:

y=4x+4

Hence, the answer is:

• It represents a Linear Function.

,

• Equation:

y=4x+4

8 0
1 year ago
Find the equation of the graphed line and select the best answer from the choices provided.​
klemol [59]

Answer:

D

Step-by-step explanation:

The y-intercept must be at -7, so that eliminates C.

Because of the direction of the line, the slope needs to be negative. This eliminates B.

The slope of the line is -7/6, so D is the correct answer.

6 0
3 years ago
Write out the first four terms of the series to show how the series starts. Then find the sum of the series or show that it dive
Nostrana [21]

Answer:

The first four terms of the series are

(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})

\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n} = 14.25

Step-by-step explanation:

We know that

Sum of convergent series is also a convergent series.

We know that,

\sum_{k=0}^\infty a(r)^k

If the common ratio of a sequence |r| <1 then it is a convergent series.

The sum of the series is \sum_{k=0}^\infty a(r)^k=\frac{a}{1-r}

Given series,

\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}

=(9+3)+(\frac97+\frac35)+(\frac9{7^2}+\frac3{5^2})+(\frac9{7^3}+\frac3{5^3})+.......

The first four terms of the series are

(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})

Let

S_n=\sum_{n=0}^\infty \frac{9}{7^n}    and     t_n=\sum_{n=0}^\infty \frac{3}{5^n}

Now for S_n,

S_n=9+\frac97+\frac{9}{7^2}+\frac9{7^3}+.......

    =\sum_{n=0}^\infty9(\frac 17)^n

It is a geometric series.

The common ratio of S_n is \frac17

The sum of the series

S_n=\sum_{n=0}^\infty \frac{9}{7^n}

    =\frac{9}{1-\frac17}

    =\frac{9}{\frac67}

    =\frac{9\times 7}{6}

    =10.5

Now for t_n

t_n= 3+\frac35+\frac{3}{5^2}+\frac3{5^3}+.......

    =\sum_{n=0}^\infty3(\frac 15)^n

It is a geometric series.

The common ratio of t_n is \frac15

The sum of the series

t_n=\sum_{n=0}^\infty \frac{3}{5^n}

    =\frac{3}{1-\frac15}

    =\frac{3}{\frac45}

    =\frac{3\times 5}{4}

    =3.75

The sum of the series is \sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}

                                        = S_n+t_n

                                       =10.5+3.75

                                       =14.25

4 0
3 years ago
10 – 7x = 2 - 8x help :)
Rudik [331]
10-7x=2-8x

We move all terms to the left:

10-7x-(2-8x)=0

We add all the numbers together, and all the variables

-7x-(-8x+2)+10=0

We get rid of parentheses

-7x+8x-2+10=0

We add all the numbers together, and all the variables

x+8=0

We move all terms containing x to the left, all other terms to the right

x=-8
4 0
3 years ago
Read 2 more answers
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