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3 years ago

6

meeta's mother is four times as old a Meeta. After five years, her mother will be three times as old as she will be then. What a

re their present ages?

1 answer:

gulaghasi [49]3 years ago

4 0

Answer:

Mother is 16 and Meeta is 4

You might be interested in

y=3x+3 y=−2x+3 how many solutions does the system have

allochka39001 [22]

Answer: One solution

Step-by-step explanation:

y = 3x + 3

y = -2x + 3

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To solve this, you need to understand a few things:

a) If two lines have the same slope but different y-intercepts, they are parallel when graphed and thus do not have any solutions

b) If two lines have the same slope and same y-intercepts, they are the same line when graphed and thus do not have infinitely many solutions

c) If two lines have different slopes (and/or y-intercepts), they have one solution

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These two lines have different slopes but the same y-intercept (condition c)

So they have one solution

5 0

2 years ago

Use a graphing calculator to approximate the vertex of the graph of the parabola defined by the following

gregori [183]

Answer:

(1/4, 5 7/8)

Step-by-step explanation:

The vertex is the extreme point of the graph. Here, it is a minimum.

For this quadratic function, a graphing calculator can tell you exactly what the vertex is. (No approximation is required.)

__

The graphing calculator in the attachment shows the vertex is ...

(0.25, 5.875) = (1/4, 5 7/8)

8 0

2 years ago

I need help with this . I don’t get how

Svetradugi [14.3K]

Simply collect like terms, numbers and or variables that have the same number and type of variable.

For example 15x^2 and 10x^2 are like terms. Circle the sign in front of the term to perform the correct operation.

5 0

3 years ago

if you roll a fair 6-sided die 9 times, what is the probability that at least 2 of the rolls come up as a 3 or a 4?

Kay [80]

Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

There are 9 rolls, hence $n = 9$ .

Of the six sides, 2 are 3 or 4, hence $p = \frac{2}{6} = 0.3333$

The desired probability is:

$P(X \geq 2) = 1 - P(X < 2)$

In which:

$P(X < 2) = P(X = 0) + P(X = 1)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{9,0}.(0.3333)^{0}.(0.6667)^{9} = 0.026$

$P(X = 1) = C_{9,1}.(0.3333)^{1}.(0.6667)^{8} = 0.117$

Then:

$P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857$

0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

7 0

2 years ago

Use the boundedness theorem to determine whether the polynomial function satisfies the given condition. The polynomial f(x) = x4

7nadin3 [17]

Answer:

So f(x) has no real greater than 8. Step - by - step explanation is shown in the attachment.

Step-by-step explanation:

Let f ( x) be a polynomial with real coefficients and with a positive lending coefficient.

If f(x) is divided by x-c and

a) if c>0 and all number in the bottom row of the synthetic division are non negative , then f(x) has no zero greater than c.

b ) if c<0 and the number in the bottom row of the synthetic division alternate in sign then f (x) has no zero less than c

As shown in the figure

Since the number in the bottom row of the synthetic division alternate in sign

So f(x) has no real greater than 8

6 0

3 years ago