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atroni [7]
3 years ago
6

meeta's mother is four times as old a Meeta. After five years, her mother will be three times as old as she will be then. What a

re their present ages?​
Mathematics
1 answer:
gulaghasi [49]3 years ago
4 0

Answer:

Mother is 16 and Meeta is 4

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MR.Trek made some trail mix for his backpacking team. He used 2 1/2 cups of granola, 1 3/4 cups of peanuts, 1 1/3 cups of raisin
valentina_108 [34]
6 7/12 of trail mix . This is the answer

if you want me to explain then just comment back
6 0
3 years ago
Cuál es primer número natural o entero positivo que conoces​
____ [38]

Answer:

Los números naturales incluyen solo enteros positivos y comienzan desde 1 hasta infinito

5 0
2 years ago
A scuba diver starts at 85 3/4 meters below the surface of the water and descends until he reaches 103 1/5
RSB [31]

Answer:

From his starting point of 85 3/4, he descended 17 9/20 meters

Step-by-step explanation:

We want to know how much farther he went down from his starting point.

103 1/5 - 85 3/4

S

tart off by making the denominators of both the numbers the same.

103 1/5 - 85 3/4

103 4/20 - 85 15/20

Make them into improper fractions

2064/20 - 1715/20 = 349/20

Make 349/20 into a mixed fraction

17 9/20

5 0
2 years ago
Find the sum of the first 48 terms of the following series, to the nearest integer.
Andru [333]

Answer:

3,672

Step-by-step explanation:

Given the sequence 6, 9, 12...

The sequence is an arithmetic sequence

first term a = 6

common difference d = 9 - 6 = 12 - 9 = 3

number of terms n = 48

Sn = n/2[2a+(n-1)d]

Substitute the given values

S48 = 48/2[2(6)+(48-1)(3)]

S48 = 24(12+(3*47))

S48 = 24(12+141)

S48 = 24(153)

S48 = 3,672

Hence the sum of the first 48terms is 3,672

8 0
3 years ago
Find the first term, a1, of an arithmetic sequence if a12 = 38 and a45 = 170.
snow_lady [41]
Standard formula for arithmetic sequence:
an = a0 + d(n-1)

if we use the two terms given, setting a12 as starting term and a45 as the end term an.

170 = 38 + 33d 
170 - 38 = 33d
132 = 33d

132/33 = d
This is the common difference, use it to find the first term.

38 = a0 + (132/33)(12-1)
38 = a0 + (132/33)(11)
38 = a0 + 132/3
38 - 132/3 = a0
38 - 44 = a0
-6 = a0

The starting term is -6

8 0
3 years ago
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