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2 years ago

Can someone pls solve for y

Mathematics

1 answer:

Paha777 [63]2 years ago

8 0

Answer:

y =7.642881742

Step-by-step explanation:

tan A = opp side/adjacent side

tan 63 = 15/y

y tan 63 = 15

y = 15/ tan 63

y =7.642881742

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If (fx)=5x, what is f^-1(x)

zysi [14]

Answer:

x/5

Step-by-step explanation:

To get the inverse function you need to leave the x alone and then switch variables ( f(x) = y)

f(x) = 5x

y = 5x

y/5 = x

Now that x is alone you switch the x for y and the y for x and you get:

x/5 = y

And this new y is the inverse function of f(x) ( f^-1(x))

f^-1(x) = x/5

6 0

3 years ago

Create a matrix that is equal to F+G. The first matrix below is named F and the second matrix below is named G. Name the new mat

likoan [24]

F+G:

$F+G=\begin{bmatrix}{-1.8} & {-8.6} & {} \\ {2.85} & {-1.4} & {} \\ {-1.8} & {5.1} & {}\end{bmatrix}+\begin{bmatrix}{1.32} & {-1.9} & {} \\ {2.25} & {0.0} & {} \\ {-6.2} & {1.4} & {}\end{bmatrix}$

Then, add the elements that occupy the same position:

$H=\begin{bmatrix}{-1.8+1.32} & {-8.6+(-1.9)} & {} \\ {2.85+2.25} & {-1.4+0.0} & {} \\ {-1.8+(-6.2)} & {5.1+1.4} & {}\end{bmatrix}$

Solve

$H=\begin{bmatrix}{-0.48} & {-10.5} & {} \\ {5.1} & {-1.4} & {} \\ {-8} & {6.5} & {}\end{bmatrix}$

So, we find the element at address h31:

$H=\begin{bmatrix}{h11} & {h12} & {} \\ {h21} & {h22} & {} \\ {h31} & {h32} & {}\end{bmatrix}$

In this case, position h31 is - 8.0

8 0

1 year ago

PLS HELP ASAP!!! I WILL GIVE BRAINLIEST!!

denis-greek [22]

Answer:

The fish is closer to the surface of the water because |+4| = 4 and |−3| = 3, and 3 < 4.

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Triangle ABC has vertices at A(–2, 3), B(–3, –6), and C(2, –1). Is triangle ABC a right triangle? If so, which angle is the righ

Len [333]

Answer:

∠ACB is a right angle

Graph:

4 0

3 years ago

Given: Angle 2 is 65 degrees. What is the angle measurement of Angle 4. Explain the angle relationship used and show your work.

lesya [120]

Answer:

$\angle 4 = 115^{\circ}$

$\angle 3 = 65^{\circ}$

$\angle 7 = 65^{\circ}$

Step-by-step explanation:

Given

$\angle 2 = 65^{\circ}$

See attachment

Solving (a): $\angle 4$

To solve for $\angle 4$ , we make use of:

$\angle 2 +\angle 4 = 180^{\circ}$

The relationship between both angles is that they are complementary angles

Make $\angle 4$ the subject

$\angle 4 = 180^{\circ} - \angle 2$

Substitute $65^{\circ}$ for $\angle 2$

$\angle 4 = 180^{\circ} - 65^{\circ}$

$\angle 4 = 115^{\circ}$

Solving (b): $\angle 3$

To solve for $\angle 3$ , we make use of:

$\angle 3 =\angle 2$

The relationship between both angles is that they are complementary angles

$\angle 3 = 65^{\circ}$

Solving (c): $\angle 7$

To solve for $\angle 7$ , we make use of:

$\angle 7 = \angle 3$

The relationship between both angles is that they are alternate exterior angles.

So:

$\angle 7 = 65^{\circ}$

7 0

2 years ago