All categories

2 years ago

Can someone pls solve for y

Mathematics

1 answer:

Paha777 [63]2 years ago

8 0

Answer:

y =7.642881742

Step-by-step explanation:

tan A = opp side/adjacent side

tan 63 = 15/y

y tan 63 = 15

y = 15/ tan 63

y =7.642881742

You might be interested in

Evaluate the expression. 42+5⋅32−42÷23 CLEAR CHECK 12.625 222 45 59

lidiya [134]

Answer:

$\frac{4604}{23}$ or 200.173913

Step-by-step explanation:

$42+(5)(32)-\frac{42}{23} \\\\=42+160-\\\frac{42}{23}\\\=202-\frac{42}{23} =\frac{4604}{23}$

5 0

3 years ago

Select all of the terms that are "like." xy2 2xy x2 -xy 2x2y 1/2xy

irakobra [83]

Hi,
The like terms are 2xy, -xy and (1/2)xy, since they have the same variables and powers.

4 0

3 years ago

#3 Solve and graph the inequality: -4+x<-9

Vanyuwa [196]

Add 4 to both sides
x < -5

Closed circle at x = 5, line points left

7 0

3 years ago

What is the factored form of the expression? d^2 = 36d + 324

Veseljchak [2.6K]

Answer:

$(x-43.45)(x+7.45)=0$

Step-by-step explanation:

We have the quadratic equation $d^{2}=36d+324$ i.e. $d^{2}-36d-324=0$

As, the roots of the quadratic equation $ax^{2}+bx+c=0$ are given by $x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$ .

So, from the given equation, we have,

a = 1, b = -36 , c = -324.

Substituting the values in $x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$ , we get,

$x=\frac{36\pm \sqrt{(-36)^{2}-4\times 1\times (-324)}}{2\times 1}$

i.e. $x=\frac{36\pm \sqrt{1296+1296}}{2}$

i.e. $x=\frac{36\pm \sqrt{2592}}{2}$

i.e. $x=\frac{36\pm 50.9}{2}$

i.e. $x=\frac{36+50.9}{2}$ and $x=\frac{36-50.9}{2}$

i.e. $x=\frac{86.9}{2}$ and $x=\frac{-14.9}{2}$

i.e. x = 43.45 and x = -7.45

Thus, the roots of the equation are 43.45 and -7.45.

Hence, the factored form of the given expression will be $(x-43.45)(x+7.45)=0$

3 0

2 years ago

Which two of the following is continuous data?

Alla [95]

Answer:

B. Age of student

D. Time taken to run 1 mile

Step-by-step explanation:

From the list of given options, only B and D satisfy the required condition.

One unique determinant of continuous data is that; they are measured and not counted.

Now, let's categorize option A to D into two

1. Counted data

2. Measured data

Options that fall into the category of measured data are said to be continuous data.

A. Concert attendance; The number of people in a concert is counted

B. The age of a student is measured (in years)

C. Number of pens in a box is counted

D. Time taken to run 1 mile is measured (in units like seconds, minutes, hours, etc...)

In summary; we have

Counted

A. Concert Attendance

C. Number of pens in a box

Measured

B. Age of a student

D. Time taken to run 1 mile

Hence, the continuous data are Age of a student and Time taken to run 1 mile

7 0

3 years ago