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3 years ago

Can someone pls solve for y

Mathematics

1 answer:

Paha777 [63]3 years ago

8 0

Answer:

y =7.642881742

Step-by-step explanation:

tan A = opp side/adjacent side

tan 63 = 15/y

y tan 63 = 15

y = 15/ tan 63

y =7.642881742

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What's the radius of a circle with an area of 64 square feet?

NeX [460]

R ≈ 4.51 ft The Area is 64 feet the power of 2. Hope this helps! :)

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3 years ago

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Solve 2sin2(x) – 5sin(x) – 3 = 0. Let u = sin(x). Which of the following is equivalent to the given equation?

Orlov [11]

Answer:

$x=(-1)^{k+1}\cdot \dfrac{\pi}{6}+\pi k,\ k\in Z$

Step-by-step explanation:

Consider the equation

$2\sin^2x-5\sin x-3=0$

Substitute

$u=\sin x$

into the equation:

$2u^2-5u-3=0$

This is quadratic equation, where

$D=(-5)^2-4\cdot 2\cdot (-3)=25+24=49\\ \\\sqrt{D}=7$

Hence,

$u_1=\dfrac{-(-5)-\sqrt{D}}{2\cdot 2}=\dfrac{5-7}{4}=-\dfrac{1}{2}\\ \\u_2=\dfrac{-(-5)+\sqrt{D}}{2\cdot 2}=\dfrac{5+7}{4}=3$

Now, use the substitution again:

1. When $u_1=-\dfrac{1}{2},$ then

$\sin x=-\dfrac{1}{2}\\ \\x=(-1)^k\sin^{-1}\left(-\dfrac{1}{2}\right)+\pi k,\ k\in Z\\ \\x=(-1)^k\cdot \left(-\dfrac{\pi}{6}\right)+\pi k,\ k\in Z\\ \\x=(-1)^{k+1}\cdot \dfrac{\pi}{6}+\pi k,\ k\in Z$

2. When $u_2=3,$ then

$\sin x=3$

This equation has no solutions, because the range of $\sin x$ is $[-1,1]$ and 3>1.

4 0

4 years ago

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Solve;<br><img src="https://tex.z-dn.net/?f=10x%20-%203%20%3D%205x%20%2B%2012" id="TexFormula1" title="10x - 3 = 5x + 12" alt="1

erastovalidia [21]

Answer:

$x = 3$

Step-by-step explanation:

$1 0x -3 + 3 = 5 + 1 2 + 3$

$1 0 x = 5 + 1 5$

$1 0 x - 5x = 5 x + 1 5 - 5x$

$5x=15$

$\frac{5x}{5} = \frac{15}{5}$

$x = 3$

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3 years ago

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For each group of three forces below, determine whether the forces in each pair are pulling at right angles to each other. 13 lb

Alex17521 [72]

From the given problem, I gather that there are only two groups of forces. These are:
13 lb, 35 lb, resultant force 30 lb
20 lb, 15 lb, resultant force 25 lb

We use the pythagorean theorem to determine if the three forces are grouped correctly, such that the resultant force is the hypotenuse.

Resultant Force = √(a² + b²)

So, for the first group,
30 ? √(13² + 35²)
30 ≠ 37.33
Thus, the first group does not pull at right angles to each other.

For the second group,
25 ? √(20² + 15²)
25 = 25
Thus, the second group does pull at right angles to each other.

7 0

4 years ago

Y - 0.8x = 0.5

Sveta_85 [38]

Answer:

$y=\frac{5+8x}{10} , x=x$

Step-by-step explanation:

y-0.8x=0.5

y*10-0.8x*10=0.5*10

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10y-8x+8x=5+8x

10y/10=5/10+8x/10

y=5+8x/10

5*5+8x/10-2.5

8x+5/2-2.5=4x

y=5+8x/10, x=x

7 0

4 years ago