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3 years ago

Opposite of -(-24). Explain how you did it please so I get an ideo of what to do for the rest

Mathematics

2 answers:

Vsevolod [243]3 years ago

6 0

in multiplication, a negative and a negative equal a positive. so the answer is 24.

Nadusha1986 [10]3 years ago

3 0

The negative outside the parentheses and the negative in the parentheses make a smiley face so they cancel out making the 24 positive.

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Simplify these 12 radicals:

Alexandra [31]

1)
$4 \sqrt{5}$
2)
$8$
3)
$3 \sqrt{5}$
4)
$3 \sqrt{6}$
5)
$4 \sqrt{2}$
6)
$6$
7)
$5 \sqrt{6}$

8)
$2 \sqrt{5}$
9)
$6 \sqrt{5}$
10)
$6 \sqrt{2}$
11)
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6 0

3 years ago

Find the size of each of the unknown angles.

kari74 [83]

Answer:

Angle a = 80°, Angle b = 55°, Angle c = 45°, Angle d = 80°

Step-by-step explanation:

To find the measure of Angle a, we add 55 and 45, then subtract the sum from 180.

180 - 100 = 80

Angle a is 80°.

Then, we solve for Angle b. Line segment CD is congruent to Line AB, so Angle b is congruent to 55°.

After that, we find Angle c. Line segment AC is congruent to Line segment BD, so Angle c is congruent to 45°.

Lastly, we solve for Angle d using the same method we used for Angle b and Angle c. Angle d is congruent to Angle a, so it measures 80°.

So, Angle a = 80°, Angle b = 55°, Angle c = 45°, Angle d = 80°.

8 0

3 years ago

Please i need your help to solve this question. I will give the brainliest.

Maksim231197 [3]

Step-by-step explanation:

The angle between vectors is given by

$\cos{\theta} = \dfrac{\vec{\textbf{a}}\cdot \vec{\textbf{b}}}{|\vec{\textbf{a}}||\vec{\textbf{b}}|}$

The magnitudes for the vectors are as follows:

$|\vec{\textbf{a}}| = \sqrt{a_x^2 + a_y^2 + a_z^2}$

$\:\:\:\:\:\:\:=\sqrt{(2)^2 +(-5)^2 + (3)^2} = 6.16$

$|\vec{\textbf{b}}| = \sqrt{b_x^2 + b_y^2 + b_z^2}$

$\:\:\:\:\:\:\:= \sqrt{(3)^2 + (1)^2 + (4)^2} = 5.10$

The dot product between the vectors is

$\vec{\textbf{a}}\cdot \vec{\textbf{b}} = (2)(3) + (-5)(1) + (3)(4) = 13$

Therefore, the angle between the two vectors is

$\cos{\theta} = \dfrac{\vec{\textbf{a}}\cdot \vec{\textbf{b}}}{|\vec{\textbf{a}}||\vec{\textbf{b}}|} = \dfrac{13}{(6.16)(5.10)}$

$\theta = 65.56°$

8 0

2 years ago

How do u teach long division

zavuch27 [327]

Explanation:

To do long division, follow the method pattern "DMS down".

D for divide.

M for multiply.

S for subtract.

Down is to bring down.

Use an example:

52 ÷ 2?

Divide 2 by the first digit of 52.

2 Whenever you divide, put the answer at the top.

2∫52

Multiply answer by number you are dividing by.

2∫52

4 When not dividing, put the work under the question.

Subtract.

2∫52

4

Bring down the next digit.

2∫52

4

Divide into the new difference 12.

2∫52

4

Multiply the new digit.

2∫52

4

Subtract.

2∫52

4

12

0 You stop when you get to 0. If you ran out of digits to bring down, write this as a remainder.

7 0

3 years ago

Read 2 more answers

T + (-5) = 14 can someone solve the equation please?

Alja [10]

Answer: 19

Add 5 to both sides

t - 5 = 14

t - 5 + 5 =14 + 5

Simplify

T=19

Hope this helped

4 0

2 years ago

Read 2 more answers