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2 years ago

Opposite of -(-24). Explain how you did it please so I get an ideo of what to do for the rest

Mathematics

2 answers:

Vsevolod [243]2 years ago

6 0

in multiplication, a negative and a negative equal a positive. so the answer is 24.

Nadusha1986 [10]2 years ago

3 0

The negative outside the parentheses and the negative in the parentheses make a smiley face so they cancel out making the 24 positive.

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NO LINKS!!!!

mixer [17]

Hope this help!!!

Have a nice day!!!

7 0

2 years ago

Find the number 17% of which is 27 more than 14% of it.

Kay [80]

The original number would be 900

5 0

2 years ago

The Ohio Department of Agriculture tested 203 fuel samples across the state in 1999 for accuracy of the reported octane level. F

OlgaM077 [116]

Answer:

The Sample size is 1918.89035

Step-by-step explanation:

Consider the provided information.

It is given that 14 out of 105 samples failed.

Therefore p = 14/105 = 0.13 3... and q=1-0.133=0.867

Samples would be needed to create a 99 percent confidence interval.

Subtract the confidence level from 1, then divide by two.

$\frac{(1 -0.99)}{2}=0.005$

By standard normal table z=2.5758≈2.58

Calculate the sample size as:

$n=\frac{z^2pq}{e^2}$

Where, e is the margin of error,

Substitute the respective values.

$n=\frac{(2.58)^2(0.133)(0.867)}{(0.02)^2}=1918.89$

Hence, the Sample size is 1918.89035

4 0

2 years ago

What is the answer for number 12

GalinKa [24]

(3*4)+(1*7)/7*4 = 12+7/28 = 19/28

your answer is 19/28

4 0

2 years ago

Read 2 more answers

true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp

Goshia [24]

Answer:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

$\mu = 114, \sigma = 40$

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

6 0

2 years ago