Let C be the number of cats of the superhero. With this, the number of cats of nemesis have is 3C/4 + 7. The numbers should be equal such that,
C = 3C/4 + 7
The value of C from the equation is 28. Thus, the number of cats of the nemesis is 28.
The answer is 35.
........
let's notice the tickmarks on the left and right sides, meaning those two sides are twins, and therefore equal, so the perimeter is simply 2.5+2.5+3.5+2.5 = 11 ft.
the trapezoid has an altitude/height of 2 ft, thus
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=2.5\\ b=3.5\\ h=2 \end{cases}\implies A=\cfrac{2(2.5+3.5)}{2}\implies A=6](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20a%2Cb%3D%5Cstackrel%7Bbases%7D%7Bparallel~sides%7D%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D2.5%5C%5C%20b%3D3.5%5C%5C%20h%3D2%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B2%282.5%2B3.5%29%7D%7B2%7D%5Cimplies%20A%3D6)
The length of the altitude is 9.5 cm.
The altitude bisects the base of the equilateral triangle (this is because the two sides emerging from the vertex are equal). This gives us a right triangle with leg 5.5 and hypotenuse 11. We use the Pythagorean theorem:
5.5² + h² = 11²
30.25 + h² = 121
Subtract 30.25 from both sides:
30.25 + h² - 30.25 = 121 - 30.25
h² = 90.75
Take the square root of both sides:
√h² = √90.75
h = 9.5
Change the fractions so they have common denominators. For example. If adding 4/8 + 2/3, a common denominator of the two could be 24. Change both fractions to have a denominator of 24. To do this:
(4/8)×(3/3)= 12/24
(2/3)×(8/8)=16/24
Now that both fractions have denominators of 24, you can simply add the numerators to get your answer. in this case, it would be 28/24
