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3 years ago

The sum of two consecutive odd integers is 84. Find the two integers.

Mathematics

2 answers:

-BARSIC- [3]3 years ago

7 0

Answer:

41 and 43.

Step-by-step explanation:

We can divide 84 by 2 and add and subtract 1 from the result to get 41 and 43 as the two numbers. For any number n that is divisible by 2, we can solve this problem by finding n/2 + 1 and n/2-1. These will always be consecutive odd numbers and if you add them up, you get n.

Rudik [331]3 years ago

5 0

Answer: n + (n + 2) = 84

Step-by-step explanation:

If n is the smallest integer, the other integer must be two more than that, because it has to be odd. The two numbers add up to 84, so the other side of the equation is 84.

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Suppose that θ is an acute angle of a right triangle and that sec(θ)=52. Find cos(θ) and csc(θ).

insens350 [35]

Answer:

$\cos{\theta} = \dfrac{1}{52}$

$\csc{\theta} = \dfrac{52}{\sqrt{2703}}$

Step-by-step explanation:

To solve this question we're going to use trigonometric identities and good ol' Pythagoras theorem.

a) Firstly, sec(θ)=52. we're gonna convert this to cos(θ) using:

$\sec{\theta} = \dfrac{1}{\cos{\theta}}$

we can substitute the value of sec(θ) in this equation:

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b) since right triangle is mentioned in the question. We can use:

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we know the value of cos(θ)=1\52. and by comparing the two. we can say that:

length of the adjacent side = 1
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we can find the third side using the Pythagoras theorem.

$(\text{hyp})^2=(\text{adj})^2+(\text{opp})^2$

$(52)^2=(1)^2+(\text{opp})^2$

$\text{opp}=\sqrt{(52)^2-1}$

$\text{opp}=\sqrt{2703}$

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we can find the sin(θ) using this side:

$\sin{\theta} = \dfrac{\text{opp}}{\text{hyp}}$

$\sin{\theta} = \dfrac{\sqrt{2703}}{52}}$

and since $\csc{\theta} = \dfrac{1}{\sin{\theta}}$

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Step-by-step explanation:

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