Question:
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of the numbers 1 through 6 on each side. She has one throw of the dice left, and she needs a 17 to win the game. What is the probability that Morgan wins the game (order matters)?
Answer:
1/72
Step-by-step explanation:
<em>Morgan can roll a 17 in 3 different ways. The first way is if the first die comes up 5, the second die comes up 6, and the third die comes up 6. The second way is if the first die comes up 6, the second die comes up 5, and the third die comes up 6. The third way is if the first die comes up 6, the second die comes up 6, and the third die comes up 5. For each way, the probability of it occurring is 1/6 x 1/6 x 1/6 = 1/216. Therefore, since there are 3 different ways to roll a 17, the probability that Morgan rolls a 17 and wins the game is 1/216 + 1/216 + 1/216 = 3/216 = 1/72</em>
<em>I had this same question on my test!</em>
<em>Hope this helped! Good Luck! ~LILZ</em>
Answer:
A. No, because two points with the same x-value have different y-values.
Step-by-step explanation:
No, because it doesn't pass the Vertical Line Test:
A. No, because two points with the same x-value have different y-values.
Answer:
A=2πrh
Step-by-step explanation:
A=2*22/7*4*9
=230
76 kilometers per day.
Step by step
468 divided by 6 = 76
76•6=468
If that's an addition sign, then b=-35.
If it's a division sign, then b=-150
Sorry I can't see which it is! Hope this helped though :)
Good luck!
