What is the smallest working unit of living things?

Biology

1 answer:

Ede4ka [16]3 years ago

6 0

A. the cell is the smallest working unit of living things

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Mitochondria and chloroplasts are similar because they are both...................in eukaryotic cells.

Tomtit [17]

Answer:

present

Explanation:

Otherwise the only similarity is that they are organelles, and can generate themselves.

6 0

3 years ago

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Which of the following statements is generally true of aneuploidies in newborns? a. An aneuploidy resulting in the deletion of a

Novay_Z [31]

Answer:

d. Monosomy X is the only viable monosomy known to occur in humans.

Explanation:

Human have 22 pair of homologous chromosomoses and an extra pair of sex chromosomes. While in males the sex chromosomes are X and Y , females have two chromosomes X . Anyway, in normal conditions the total number of chromosomomes that humans have in their cells is 46 (23 pair of chromosomes).

Aneuploidy is a biological condition where an individual have an abnormal number of chromosomes in their cells. In humans for examples, this would be a human having more or less than 46 chromosomes.

The Turner syndrome also called monosomy X is an aneuploidy where one of the X chromosomes is missing in a female. Although under constant supervision, people with Turner syndrome have viable healthy lives. However this is the only monosomy that occur in humans that is compatible with life.

4 0

3 years ago

Glucose-6-phosphate dehydrogenase deficiency (G6PD) is inherited as an X-linked recessive allele in humans. A woman whose father

prohojiy [21]

Answer:

(a) 1/2; (b) no

Explanation:

Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked recessive disorder and the woman's father was diseased so it means that woman is a carrier of the allele but has normal phenotype. It means that she will have XXᵇ genotype.

In contrast to this, her husband is diseased so his genotype will be XᵇY.

The Punnett square diagram related to the cross is attached.

(a) Proportion of their sons expected to be G6PD is 1/2:

They both may give birth to 4 progeny with genotypes XXᵇ, XᵇXᵇ, XY and XᵇY. It means they both may have 2 sons out of which one with genotype XᵇY will be diseased while the one with genotype XY will be healthy. So the proportion of their sons having G6PD is 1/2 or 50%.

(b) If the husband were G6PD deficient, the answer will not change.

The reason behind this is that this disease is caused by an allele located in X chromosome. But father contributes only Y chromosome to his son not X chromosome. The X chromosome will affect the genotype of his daughter not son that is why answer will not change. It means they will still have 1/2 of their sons diseased.