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Akimi4 [234]
2 years ago
10

Hong buys candy that cost 8$ per pound. He will buy at least 5 pounds of candy. What are the possible amounts he will spend on c

andy?
Mathematics
1 answer:
DENIUS [597]2 years ago
8 0

Answer:

8*5≥c  

Step-by-step explanation:

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Are BD and CE congruent? Explain.
Alona [7]

Answer:

The answer is D: Yes, BD = 7 and CE = 7

Step-by-step explanation:

B--> -5

D --> 2

-5 + BD = 2

BD = 7

C--> 0

E --> 7

0+CE=7

CE = 7

The answer is D

3 0
3 years ago
What is the area of this rectangle 6.03cm 3.4cm. cm2
Arlecino [84]
You'll have to be more specific, like what is each side, as in height, width or length. Sorry!
4 0
3 years ago
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The tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm2 and a stand
Elanso [62]

Answer:

95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment.

Step-by-step explanation:

We are given that the tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm 2 and a standard deviation of 2.15.

A machine was recently adjusted and a sample of 50 items were taken to determine if the mean tensile strength has changed. The mean of this sample is 74.28. Assume that the standard deviation did not change because of the adjustment to the machine.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                         P.Q. = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean strength of 50 items = 74.28

            \sigma = population standard deviation = 2.15

            n = sample of items = 50

            \mu = population mean tensile strength after machine was adjusted

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

So, 95% confidence interval for the population mean, \mu is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                  significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u><em>95% confidence interval for</em></u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                 = [ 74.28-1.96 \times {\frac{2.15}{\sqrt{50} } } , 74.28+1.96 \times {\frac{2.15}{\sqrt{50} } } ]

                 = [73.68 kg/mm2 , 74.88 kg/mm2]

Therefore, 95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

<em>Yes, this data suggest that the tensile strength was changed after the adjustment as earlier the mean tensile strength was 72 kg/mm2 and now the mean strength lies between 73.68 kg/mm2 and 74.88 kg/mm2 after adjustment.</em>

8 0
3 years ago
Which statements are true?
Nimfa-mama [501]
All rectangles are parallelograms. Hope this helps.
4 0
3 years ago
Read 2 more answers
Bethany has 3.10$ in nickels and dimes. She has a total of 44 coins . What is the value of the nickels Bethany has
vlada-n [284]
Represent the unknows with n and d.

Then n+d = 44 (# of coins)

and 

$0.05n + $0.10d = $3.10   (value of coins)

Solving the first equation for n, we get n = 44-d.  Subst.  44-d for n in the 2nd equation:

0.05(44-d) + 0.10d = 3.10
Then 2.20 - 0.05d + 0.10d = 3.10, or
          2.20 + 0.05d             = 3.10, or    0.05d = 0.90.  Solving for d, 
       0.90
d = -------- = 18
        0.05

There are 18 dimes and 44-18 nickels.  How many nickels is that?  ;)

5 0
3 years ago
Read 2 more answers
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