When the entropy change of vaporization
= enthalpy of vaporization/boiling point temperature
when we have the enthalpy of vaporization = 38560 J/mol
and the boiling point temperature in Kelvin = 78.3 + 273 = 351.3 K
by substitution:
∴the entropy change of vaporization = 38560J/mol/351.3K
= 109.76 J/K/mol
and when the liquid has lesser entropy than the gas and we here convert from
gas to liquid so, the change in entropy = -109.76 J/K/mol
now, we need the moles of C2H5OH = mass/molar mass when the molar
mass of C2H5OH = 46 g/mol and mass = 42.2 g
∴ moles of C2H5OH = 42.2 g / 46 g/mol = 0.92 moles
when 1 mol of C2H5OH turns in liquid entropy change →-109.76 J/K/mol
∴ 0.92 mol of C2H5OH → X
∴ X entropy change when 0.92 mol = -109.76 *0.92 mol / 1 mol
= 84.64 J/K
If you go by the decimal there should be 5 significant digits because 0 is a trailing zero and matters since it comes after a decimal. however if you do
6.3590 x 10 ^7 = 63590000 then you would only have 4 significant digits because there is no longer a decimal to make the zero after the 9, significant.
Hope this helps!
Answer:
A precipitate will be formed
Explanation:
The Ksp equilibrium of Fe(OH)₃ is:
Fe(OH)₃ (s) ⇄ Fe³⁺(aq)+ 3OH⁻(aq)
And its expression is:
Ksp = 4x10⁻³⁸ = [Fe³⁺] [OH⁻]³
<em>Where the concentrations are concentrations in molarity in equilibrium,</em>
We can write Q as:
Q = [Fe³⁺] [OH⁻]³
<em>Where [] are actual concentrations in molarity of each specie.</em>
<em />
When Q>= Ksp; a precipitate is formed,
When Q< Ksp no precipitate is produced:
[OH⁻] = [NaOH] = 1.0x10⁻⁴M
[Fe²⁺] = 2.50x10⁻²g * (1mol / 179.85g) / 0.100L = 1.39x10⁻³M
<em>179.85g/mol is molar mass of Fe(NO₃)₂ and the volume of the solution is 0.100L = 100mL</em>
<em />
Q = [Fe³⁺] [OH⁻]³
Q = [ 1.39x10⁻³] [ 1.0x10⁻⁴]³
Q = 3.8x10⁻¹⁵
As Q >> Ksp; A precipitate will be formed
Answer:
to put it simply, equilibrium is when two opposing forces balance each other out. one example is boats: you know how the bottom half is curved, and then meets at an edge? they design it like that because of water displacement. by gravity, the water wants to go back to the area taken by the boats mass (the parts where it has sunken into the water), thus preventing the boat from sinking. once the boat is removed, the water returns to the space. most liquids take form of their container.
Hi
sorry
i don’t know but maybe next time
