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Ghella [55]
3 years ago
11

Data: Beaker Test 1:Temp/VolBeaker Test 2:Temp/VolBeaker Test 3:Temp/VolBeaker Test 4:Temp/VolBeaker Test 5:Temp/VolTrial One: A

ir-14.5 °C / 4.3 mL0.9 °C / 4.7 mL21.7°C / 5.0 mL48.5 °C / 5.4 mL81.2 °C / 5.9 mLTrial Two: Nitrogen (N2)-14.5 °C / 4.4 mL0.9 °C / 4.7 mL21.7 °C / 5.1 mL48.5 °C / 5.4 mL81.2 °C / 5.9 mLData Analysis: Create a separate graph of temperature vs. volume for each of the gas samples. You are encouraged to use graphing software or online tools to create the graphs; be sure to take screenshots of the graphs that also include your data.Make sure to include the following on your graphs:•Title•Labels for axes and appropriate scales•Clearly plotted data points
Chemistry
1 answer:
miskamm [114]3 years ago
8 0
A beaker is 1,9005kg because of the size of the weight is 1,000kg=1g
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If cells did not work together what would happen to the organisms
arlik [135]

Surely, If cells did not work together in an organism, there won't be formation of new cells and life process would stop

<h3>Living organisms </h3>

Living organisms; be it plants or animals are any organic or living system composed of cells and function as an individual entity.

  • All living organisms share a number of key characteristics or functions such as movement, respiration, homeostasis, reproduction, growth, evolution, competition and others.

  • Animals and plants also posess systems such as the digestive, skeletal, transport, nervous, excretory, respiratory and reproductive system.

  • Living organisms are also taxonomically classified as either unicellular microorganisms or multicellular plants and animals

So therefore, surely, If cells did not work together in an organism, there won't be formation of new cells and life process would stop

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brainly.com/question/17259533

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5 0
1 year ago
Given the following equation: Cu + 2 AgNO3 ---&gt; Cu(NO3)2 + 2
Temka [501]

Given the following equation; Cu + 2AgNO3 = Cu(NO3)2 + 2Ag, 48.97 grams of Cu are needed to react with 262g of AgNO3.

<h3>How to calculate mass of substances?</h3>

The mass of a substance can be calculated using the following steps:

Cu + 2AgNO3 = Cu(NO3)2 + 2Ag

1 mole of Cu react with 2 moles of AgNO3

  • Molar mass of AgNO3 = 169.87 g/mol
  • Molar mass of Cu = 63.5g/mol

moles of AgNO3 = 262g/169.87g/mol = 1.54mol

1.54 moles of AgNO3 will react with 0.77 moles of Cu.

mass of Cu = 0.77 × 63.5 = 48.97g

Therefore, given the following equation; Cu + 2AgNO3 = Cu(NO3)2 + 2Ag, 48.97 grams of Cu are needed to react with 262g of AgNO3.

Learn more about mass at: brainly.com/question/6876669

8 0
3 years ago
You could add solid KCl to the solution to precipitate out AgCl(s). What mass of KCl is needed to precipitate the silver ions fr
padilas [110]

Answer:

0.143 g of KCl.

Explanation:

Equation of the reaction:

AgNO3(aq) + KCl(aq) --> AgCl(s) + KNO3(aq)

Molar concentration = mass/volume

= 0.16 * 0.012

= 0.00192 mol AgNO3.

By stoichiometry, 1 mole of AgNO3 reacts with 1 mole of KCl to form a precipitate.

Number of moles of KCl = 0.00192 mol.

Molar mass of KCl = 39 + 35.5

= 74.5 g/mol

Mass = molar mass * number of moles

= 74.5 * 0.00192

= 0.143 g of KCl.

4 0
4 years ago
Draw it draw lewis dot structures for each hypothetical molecule shown below, using the correct number of valence electrons for
soldi70 [24.7K]

The first molecule is a sensible molecule having complete octet of each atom such as C, H and O whereas the second molecule having hydrogen present between the aldehyde and methyl group and thus showing hydrogen is making bond with aldehyde and methyl as well which is not possible because hydrogen only having one electron in its octet due to which it can only form a single bond by sharing its valence electron.

6 0
4 years ago
How many moles of Co2 are produced when 0.2 moles of sodium carbonate reacts with excess HCl
Pie
To determine the number of moles of carbon dioxide that is produced, we need to know the reaction of the process. For the reaction of HCl and sodium carbonate, the balanced chemical equation would be expressed as:

2HCl + Na2CO3 = 2NaCl + H2O + CO2

From the initial amount given of sodium carbonate and the relation of the substances from the balanced reaction, we calculate the moles of carbon dioxide as follows:

0.2 moles Na2Co3 ( 1 mol CO2 / 1 mol Na2Co3 ) = 0.2 moles CO2

Therefore, the amount in moles of carbon dioxide that is produced from 0.2 moles sodium carbonate would be 0.2 moles as well.
5 0
3 years ago
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