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makkiz [27]
3 years ago
6

Uranium-235 and uranium-238 are considered isotopes of one another

Chemistry
1 answer:
Bogdan [553]3 years ago
6 0
If you are asking which is the most abundant, Uranium-238 is
You might be interested in
Consider the following operations on the number 7.02 times 10^-2. Without using a calculator, decide which would give a signific
mariarad [96]

Answer: (a). Significantly Larger value

(b). Significantly Smaller value

(c). Significantly Larger value

(d). Significantly Smaller value

Explanation:

This is quite a dicey  question to analyze, let us not get too carried away with the simplicity of the mathematical signs involved.

Given that 7.02 × 10⁻² is the number to be compared with.

(a).  7.02 × 10⁻² + 6.10 × 10⁵

from this, we can see a very large number being added to the base number involved, although the base number is carrying a negative power, it does not affect the other greatly.

ANS: the sum would give a significantly larger value

(b). 7.02 × 10⁻² - 6.10 × 10⁵

Here, we can see a very large number subtracted from the base number having a negative power.

the subtraction of this numbers gives a Significantly smaller value than the base number i.e. 7.02 × 10⁻²

ANS: Significantly smaller value

(c). 7.02 × 10⁻² × 6.10 × 10⁵

we would solve this from our basic knowledge of indices

where ⇒ (10ᵃ × 10ᵇ = 10ᵃ⁺ᵇ)

we have,

7.02 × 10⁻² × 6.10 × 10⁵ = (7.02 × 6.10) × 10⁻²⁺⁵ = (7.02 × 6.10) × 10³

this final value (multiplication value) gives a Significantly larger value.

ANS: Significantly larger value

(d). 7.02 × 10⁻² ÷ 6.10 × 10⁵

Also, we apply the indices rule for Division

where ⇒ (10ᵃ ÷ 10ᵇ = 10ᵃ⁻ᵇ)

i.e. 7.02 × 10⁻² ÷ 6.10 × 10⁵ = (7.02 × 6.10) × 10⁻²⁻⁺⁵ = (7.02 × 6.10) × 10⁻⁷

this final value gives a Significantly Smaller value

ANS: Significantly Smaller value

cheers i hope this helps.

7 0
3 years ago
λmax for the π → π* transition in ethylene is 170 nm. Is the HOMO-LUMO energy difference in ethylene greater than or less than t
-Dominant- [34]

Answer:

the HOMO-LUMO energy difference in ethylene is greater than that of cis,trans−1,3−cyclooctadiene

Explanation:

The λmax is the wavelength of maximum absorption. We could use it to calculate the HOMO-LUMO energy difference as follows:

For ethylene

E= hc/λ= 6.63×10^-34×3×10^8/170×10^-9= 1.17×10^-18J

For cis,trans−1,3−cyclooctadiene

E= hc/λ=6.63×10^-34×3×10^8/230×10^-9=8.6×10^-19J

Therefore, the HOMO-LUMO energy difference in ethylene is greater than that of cis,trans−1,3−cyclooctadiene

8 0
3 years ago
Which of the following is a basic solution? HCl dissolved in water b. household ammonia c. vinegar d. pure water
PSYCHO15rus [73]

Answer:

B. Household ammonia.

Explanation:

NH₃ is a base, so the solution always will be basic.

NH₃ takes the proton from the water. In conclusion we have free OH⁻ in medium, that's why the solution is basic.

NH₃ + H₂O → NH₄⁺  +  OH⁻

- HCl + H₂O → H₃O⁺  + Cl⁻

This reaction makes an acid solution, cause the H₃O⁺

- Vinegar is a compound made of acetic acid.

CH₃COOH  + H₂O  ⇄  H₃O⁺  +  CH₃COO⁻

This reaction also makes an acid solution, cause the H₃O⁺

- Pure water makes neutral solution. It is not acid, neither basic.

2H₂O ⇄  H₃O⁺  +  OH⁻

7 0
3 years ago
In an equimolar mixture of o2 and n2, are the mass fractions equal?
nika2105 [10]

Answer:

No

Explanation:

The mass fraction is defined as:

w_{i}=\frac{m_{i} }{m_{t} }

where:

  • wi: mass fraction of the substance i
  • mi: mass of the substance i
  • mt: total mass of the system

<u><em>The mass fraction of two substances (A and B), will be the same, ONLY if the mass of the substance A (mA) is the same as the mass of the substance B (mB).</em></u>

An equimolar mixutre of O2 and N2 has the same amount of moles of oxygen and nitrogen, just to give an example let's say that the system has 1 mole of O2 and 1 mole of N2. Then using the molecuar weigth of each of them we can calculate the mass:

mA= 1 mole of O2 * 16 g/1mol = 16 g

mB=1 mole of N2 *28 g/1mol=28 g

As mA≠mB then the mass fractions are not equal, so the answear is NO.

4 0
3 years ago
The decomposition of methanol, ch3oh(g), to form ch4(g) and o2(g) absorbs 252.8 kj of heat per mole of oxygen formed. write a ba
Svetllana [295]
The thermochemical equation is the chemical equation including the net change of enthalpy (heat).

The chemical equation for the decomposition of methanol to form methane and oxygen is:

2CH3OH --> 2CH4 + O2

The thermochemical equation is:

2CH3OH ---> 2CH4 + O2  - 252.8 kJ

Note that the heat is placed as negative at the right side because it is absorbed during the decomposition, so the environment will have 252.8 kJ less per each mole of O2 produced.

You can equivalently write:

2CH3OH + 252.8 kJ --> 2CH4 + O2
4 0
3 years ago
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