Answer:
Step-by-step explanation:
Given that A = {2, 4, 6}, B = {2, 6}, C = {4, 6}, and D = {4, 6, 8}.
We know that P is a subset of Q if all elements of P are also in Q
Using this let us compare pairwise
A and B
The elements of B are also in A
So B is a subset of A
Next A and C,
All elements of C are in A. So C is a subset of A
B and C. We find neither is a subset of other
B and D. Here also 2 is not in D so not a subset
C and D
C is a subset of D
SO answer is
B and C are subsets of A and C is also a subset of D
The answer is c,b,a. I’m pretty sure
Let P be the number of kids,
we know P>57
take 1-(1/2)-(1/5)=3/10
therefore 57 is 3/10P
3/7P=57
P=57*7/3=133 is the answer
it would be incorrect if we didnt get a positive integer.
Unable to provide a definitive answer due to lack of diagram.
Answer: 1/4
Step-by-step explanation:
Multiples of 6:
Multiples of 6 are numbers obtained when 6 is multiplied by an integer. Such as
(6*1) = 6, (6*2)=12, (6*3) = 18..... and so on.
Probability is calculated by finding the ratio of the required outcome and total possible outcomes.
Probability = required outcome / Total possible outcomes
P(multiple of 6) = number of multiples of 6 / total number of possible outcomes
If number of 6 multiples = 5 and
Total number of faces in the spinner = 20
Then :
P(multiple of 6) = 5/20 = 1/4
Since one equation has a negative y and the other has a positive y, I'm going to use those since they cancel each other out. Before that, the two y's need to be equal to each other.
x+2y=6
x-y=3
Multiply the bottom equation by two so then you have:
x+2y=6
2x-2y=6
The y's now cancel out:
x=6
2x=6
Add them together
3x=12
Divide
x=4.
To find y, plug x into either equation (*don't have to do both, but I will)
(4)+2y=6
(4)-y=3
Subtract four
2y=2
-y=-1
Divide each
2y/2 = 2/2
y=1
-y/-1 = -1/-1
y=1
The answer is:
x=4
y=1
I hope that helps!
