Answer:
C. T is not one-to-one because the standard matrix A has a free variable.
Step-by-step explanation:
Given

Required
Determine if it is linear or onto
Represent the above as a matrix.
![T(x_1,x_2,x_3) = \left[\begin{array}{ccc}1&-5&4\\0&1&-6\\0&0&0\end{array}\right] \left[\begin{array}{c}x_1&x_2&x_3\end{array}\right]](https://tex.z-dn.net/?f=T%28x_1%2Cx_2%2Cx_3%29%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-5%264%5C%5C0%261%26-6%5C%5C0%260%260%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx_1%26x_2%26x_3%5Cend%7Barray%7D%5Cright%5D)
From the above matrix, we observe that the matrix does not have a pivot in every column.
This means that the column are not linearly independent, & it has a free variable and as such T is not one-on-one
Answer:
undefined
Step-by-step explanation:
To find the slope of the line between two points, use the slope formula
.
and
represent the x and y values of one point the line passes through, and
and
represent the x and y values of another point the line also passes through. Therefore, use the x and y values of the points (0,3) and (0,4) to find the slope. Substitute them into the formula in the right order:
However, we can't divide 1 by 0. Therefore, the slope is undefined. (You could also graph the points to see that they form a vertical line, and all vertical lines have an undefined slope.)
The answer is a.2 because this coordinate is the only one along the slope
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