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My name is Ann [436]
3 years ago
13

It is known that 60% of the students at a large university have a job and 40% do not have a job. If three of these students are

randomly selected what is the probability all three have jobs?
a. 0.360
b. 0.216
c. 0.648
d. 0.060
Mathematics
1 answer:
marin [14]3 years ago
4 0

Answer:

b. 0.216

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they have a job, or they do not. The probability of a student having a job is independent of other students. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

60% of the students at a large university have a job

This means that p = 0.6

If three of these students are randomly selected what is the probability all three have jobs?

This is P(X = 3) when n = 3. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.6)^{3}.(0.4)^{0} = 0.216

So the correct answer is:

b. 0.216

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Answer:

B. Complementary Angles

Step-by-step explanation:

They both make up 90 degree angle.

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4 years ago
To subtract a fraction or a mixed number from a whole number, you’ll first need to convert the whole number to which of the foll
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IMproper fraction is what you need to covert it 2 cuz u multiply then add and u'll get it
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3 years ago
Read 2 more answers
Isotope mass (amu) abundance (%) 1 203.97304 1.390 2 205.97447 24.11 3 206.97590 22.09 4 207.97665 52.41 find the atomic mass of
Nata [24]
Answer:
average atomic mass = 207.2172085 amu

Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.

For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)

The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
                                     + 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu

Hope this helps :)
7 0
3 years ago
38% of 1200 Otto middle school students are 6th how many auto students are sixth graders
kramer

Answer:

456 students

Step-by-step explanation:

38% = 0.38

1200 x 0.38 = 456

6 0
2 years ago
Christine has always been weak in mathematics. Based on her performance prior to the final exam in Calculus, there is a 40% chan
azamat

Answer:

There are a 25% probability that Christine fails the course.

Step-by-step explanation:

We have these following probabilities:

A 50% probability that Christine finds a tutor.

With a tutor, she has a 10% probability of failling.

A 50% probability that Christine does not find a tutor.

Without a tutor, she has a 40% probability of failing.

Probability that she fails:

10% of 50%(fail with a tutor) plus 40% of 50%(fail without a tutor). So

P = 0.1*0.5 + 0.4*0.5 = 0.25

There are a 25% probability that Christine fails the course.

6 0
3 years ago
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