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bija089 [108]
4 years ago
15

The diagram below shows a sandbox and the frame that

Mathematics
1 answer:
Mashutka [201]4 years ago
3 0

Answer:

8x+16  ft^2

Step-by-step explanation:

First we find the total area of the large rectangle

A = l*w

A = (x+3) * (x+5)

FOIL

A = x^2 +5x+3x+15

A = x^2 +8x+15

Now we find the area of the inner rectangle

A = lw

A = (x+1) (x-1)

FOIL

A = x^2 -x+x -1

A = x^2 -1

To find the shaded area, take the large rectangle and subtract the small rectangle

x^2 +8x+15 - (x^2 -1)

Distribute the minus sign

x^2 +8x+15 - x^2 +1

Combine like terms

8x+16

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What is an example of when you would want consistent data and, therefore, a small standard deviation?
steposvetlana [31]

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12.1, 12.3,12.4,12.5,12.3,12.1,12.2

\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271

And for the standard deviation we can use the following formula:

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And after replace we got:

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And as we can ee we got a small value for the deviation <1 on this case.

Step-by-step explanation:

For example if we have the following data:

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We see that the data are similar for all the observations so we would expect a small standard deviation

If we calculate the sample mean we can use the following formula:

\bar X=\frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271

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s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And after replace we got:

s = 0.1496

And as we can ee we got a small value for the deviation <1 on this case.

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3 years ago
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