2 years ago

What are the domain and range of the function of the graph

Mathematics

2 answers:

alexira [117]2 years ago

8 0

The domain is the x intercept and the y intercept is the range

Oksanka [162]2 years ago

8 0

3 dot is the answer for that question

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3 years ago

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melamori03 [73]

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Step-by-step explanation:

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3 years ago

Which equation can be used to find the unknown length, b, in this triangle?

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3 years ago

-4(w+1)=-24 solve for w

sineoko [7]

Answer:

w = 5

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−4(w+1)=−24

(−4)(w)+(−4)(1)=−24(Distribute)

−4w+−4=−24

−4w−4=−24

Step 2: Add 4 to both sides.

−4w−4+4=−24+4

−4w=−20

Step 3: Divide both sides by -4.

-4w/-4 = -20/-4

w=5

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Luna G.

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3 years ago

Point a pq and r are collinear on pr and pq: pr =2/3. P is located on the origin q is located at (x,y) and r is located at (-12,

dybincka [34]

The values of x and y are 8 and 0 respectively.

Explanation

As 'p' is located at (0,0) and 'r' is located at (-12,0) , that means both 'p' and 'r' are on the x-axis. So point 'q' will be also on the x-axis , and 'q' is located at (x,y)

So, the value of y will be 0. That means the co ordinate of point 'q' is (x, 0)

Now, using the Distance formula, length of 'pq' $= \sqrt{(x-0)^2 +(0-0)^2}= \sqrt{x^2}= x$

and length of 'pr' $= \sqrt{(-12-0)^2+(0-0)^2}= \sqrt{144}=12$

Given that, pq : pr =2/3

So....

$\frac{x}{12} =\frac{2}{3}\\ \\ 3x=24\\ \\ x= \frac{24}{3}=8$

Thus, the values of x and y are 8 and 0 respectively.

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3 years ago