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andrezito [222]
2 years ago
15

HELP PLEASE !!!

Mathematics
1 answer:
saul85 [17]2 years ago
5 0
X - 4y = 12 ----(1)
y = 1/4 x - 3 ----(2)

(2)*4 ; 4y= x-12
(1) is exactly the same equation with (2)
so there are many solutions (c)
You might be interested in
A line passes through the point (4,-4) and has a slope of 5/4.
tester [92]

Answer:

y = 5/4x - 9

Step-by-step explanation:

y = mx + b

when you plot 4, -4 you have your first clue and point. then go up 5 and right 4 or down5 and left 4. When you go down you will reach the y intercept. On the number- 9. So -9 is your y intercept which goes in b.

Since 5/4 goes in the mx since it is slope the answer is y = 5/4 - 9

6 0
2 years ago
Which number(s) below belong to the solution set of the inequality? Check all that apply.x + 16 < 51.
natta225 [31]
If you subtract 16 on both sides... x will be alone. Therefore 51-16=35
x=35 (B)
5 0
2 years ago
A pet shop has rabbits and gerbils for sale. They have 20 animals altogether. They sell two rabbits. Then one of the gerbils has
Triss [41]
20 animals - 2 rabbits = 18 animals
18 animals + 2 gerbils = 20 animals.
20 animals / 4 = 5 animals
There are 5 rabbits and 15 gerbils now.
At the start 2 rabbits were sold so add that on.
5 + 2 = 7
There were 7 rabbits.
There weren't any twin gerbils then.
15 - 2 = 13.
There were 13 gerbils and 7 rabbits to start with.

Hope This Helps You!
Good Luck Studying :)
4 0
3 years ago
A square has a side length of 5. if another square is created by doubling the side length, what happens to the perimeter of the
garik1379 [7]
Its greater by a factor of 2^2 ( = 4)

Its 4 times the area of the original square.
7 0
3 years ago
What is the radius of a circle whose equation is x2 y2 8x – 6y 21 = 0?
andrew11 [14]

we know that

the standard form of the equation of the circle is

(x-h)^{2} +(y-k)^{2}=r^{2}

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

x^{2} +y^{2} +8x-6y+21=0

<u>Convert to standard form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}+8x) +(y^{2}-6y)=-21

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

(x^{2}+8x+16) +(y^{2}-6y+9)=-21+16+9

(x^{2}+8x+16) +(y^{2}-6y+9)=4

Rewrite as perfect squares

(x+4)^{2} +(y-3)^{2}=4

(x+4)^{2} +(y-3)^{2}=2^{2}

the center of the circle is (-4,3)

the radius of the circle is 2\ units

therefore

<u>the answer is</u>

the radius of the circle is 2\ units


8 0
3 years ago
Read 2 more answers
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