A door alarm works in 72 out of 100 cases.
surveillance camera works in 68 out of 100 cases.
The probability that method A is used = 72/100
The probability that method B is used = 68/100
Since both method are used we find the probability of A and B
Probability ( A and B) =
* 
=
The answer is D because it has the larger number and value. So that is the area of the circle.
Answer:

Step-by-step explanation:
-A rectangle's area is given by:

Given A=
and
, we substitute in the formula to solve for the width as follows:

Hence , the rectangle's width is 
For this equation, let b equal the cost per box.
b=$100/5