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Crank
3 years ago
13

HELP ME PLZ!! It's only 4 questions

Mathematics
1 answer:
aksik [14]3 years ago
8 0
1.) 16.25 cm 2.) Danny's container is 4.25 in bigger 3.) 148.75 inches squared 4.) 12 1/2 yd
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Mike and talia each make a scale drawing of the right side of their house. The scale of the side of the actual house to Mikes dr
Nutka1998 [239]

The width and height of Talia's Scale drawing are :

  • Width = 4.35 in
  • Height = 5.7 in

We can obtain the actual length of the side of the house from Mike's drawing :

  • Mike's scale = 3 ft to 1 in

Actual measurements:

  • Scale ratio × model drawing
  • Height, h = 9.5 × 3 = 28.5 feets
  • Width, w = 7.25 × 3 = 21.75 feets

Measurement of Talia's Scale drawing :

  • Talia's scale = 5 ft to 1 in
  • Actual measurement ÷ scale
  • Height = 28.5 ÷ 5 = 5.7 in
  • Width = 21.75 ÷ 5 = 4.35 in

The width and height of Talia's scale drawing are 5.7 and 4.35 respectively.

Learn more : brainly.com/question/17388747?referrer=searchResults

5 0
3 years ago
PLZZZ NEED HELP!!!!!!
Nuetrik [128]
Uhh thats a test...... a or b
4 0
3 years ago
Read 2 more answers
Last question...! And then I’m totally done with asking questions for a while. -v-;; Any answers or advice on how to solve?
Veseljchak [2.6K]
Multiply both sides by "x"

1 -x + 2x = 7

x = 6
6 0
3 years ago
Kiera's dance class starts at 4:30 p.m. and ends at 6:15 p.m. How long is her dance class?
qwelly [4]
From 4 PM to 6 PM is 2 hours, and it's 15 minutes after 6, so her dance class is 2 hours and 15 minutes long.
8 0
3 years ago
Read 2 more answers
Find all the zeros for each function P(x)=x^4-4x^3-x^2+20x-20
ivanzaharov [21]

Answer:

The zeros of the given polynomial function are

2,2,\pm\sqrt{5}

Step-by-step explanation:

Given polynomial is P(x)=x^4-4x^3-x^2+20x-20

To find the zeros equate the given polynomial to zero

ie., P(x)=0

P(x)=x^4-4x^3-x^2+20x-20=0

By using synthetic division we can solve the polynomial:

2_|   1     -4     -1      20      -20

       0      2     -4     -10       20

   _____________________

       1     -2      -5      10      |_0

Therefore x-2=0

x=2 is a zero of P(x)

Now we can write the cubic equation as below:

x^3-2x^2-5x+10=0

Again using synthetic division

2_|   1     -2     -5     10      

       0      2      0    -10    

    ______________

       1      0      -5     |_0

Therefore x-2=0

x=2 is also a zero of P(x).

Now we have x^2+0x-5=0

x^2-5=0

x^2=5

x^=\pm\sqrt{5} is a zero of P(x)

Therefore the zeros are 2,2,\pm\sqrt{5}

8 0
3 years ago
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