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Delvig [45]
3 years ago
10

What is the exact circumference of the circle?

Mathematics
2 answers:
san4es73 [151]3 years ago
5 0

Answer:

50.24

Step-by-step explanation:

Take the diameter and multiply by 3.14 so 16 times 3.14

wlad13 [49]3 years ago
3 0

Answer:

State that the circunference of a circle is equal to:

C=\pi d, where C is the circumference and d is the diameter

So, once d = 16 in

Therefore, C=16\pi in

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2x(x + 3) = 5x - 4standard form​
soldi70 [24.7K]

Answer:

did you make a typo? there is no real solution

Step-by-step explanation:

4 0
2 years ago
agent burn transferred classified files from the CIA Mainframe into his flash drive the drive had 36.5 megabytes on it before th
Irina-Kira [14]

Answer:

see below  PLEASE GIVE BRAINLIEST

Step-by-step explanation:

549 - 36.5 = 512.5mb were trf

512.5/125 = 4.1mb per second

4 0
2 years ago
Say you wanted to give someone 35000 berries, but every time you give someone berries, it takes away 30%. How could you calculat
VladimirAG [237]

Answer:

What I understand is that I need to give someone an exact number so that when 30% is taken, they keep exactly 35,000

To make the statement above true, we would need to divide 35,000 by 7 since the answer would be 10% of the number we need. Once we do this we get 5000 which is 10% now we multiply 5000 by 10 to get 100% and we get 50.000 once we give this amount to the person and 30% is taken away they are left with 35,000

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2 years ago
Graph the point that has the coordinates
iogann1982 [59]

Answer/Step-by-step explanation:

From the middle go left, stop between -4 and -5, then go up and stop between 2 and 3,

8 0
2 years ago
Need help finding the x, y, and z. please and thank you
Reptile [31]

The first step in any problem is to look at what you are given. When solving systems of linear equations, it is often helpful to eliminate one or more of the variables by adding or subtracting a multiple of one equation with a multiple of another. It is convenient when at least one of the multipliers is 1.

Here, we can cancel the y-terms in the 2nd and 3rd equations simply by adding them together. This gives

... (5x +y -4z) +(-3x -y +5z) = (41) +(-45)

... 2x +z = -4 . . . . simplified

Likewise, we can add 3 times the second equation to the first to cancel y in that sum.

... 3(5x +y -4z) +(2x -3y +z) = 3(41) + (-1)

...15x +3y -12z +2x -3y +z = 123 -1

...17x -11z = 122 . . . . simplified

Now that we have 2 equations in x and z, we can go through the same process. We observe that the coefficient of z is +1 in the first equation and -11 in the second. The means we can cancel the z terms by adding 11 times the first equation to the second:

... 11(2x +z) +(17x -11z) = 11(-4) +122

...22x +17x = 78 . . . . . . simplify a little bit

... x = 78/39 = 2 . . . . . . divide by 39

From above, we find

... z = -4 -2x = -4 -2·2 = -8

... y = 41 -5x +4z = 41-5(2) +4(-8) = 41 -42 = -1

The solution is (x, y, z) = (2, -1, -8).

_____

The method of elimination used here will vary with the system of equations. If you want to employ a consistent method, you can use Cramer's Rule, Gaussian elimination, or matrix methods. Since you apparently don't mind help from technology, learning to do this on your graphing calculator can also be a good idea.

4 0
2 years ago
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