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3 years ago

I know how to graph but the answer I get doesn't seem to pop up as my options

Mathematics

1 answer:

victus00 [196]3 years ago

8 0

So you found a solution that satisfies the system of equations but it's not one of the ones listed?

Then I guess what you should instead do is,
plug each of your options into the system and see which one holds true.

(1,0) = (x,y)

y = -2x+5
y = 1/2x

0 = -2(1) + 5
0 = 1/2(1)

1/2 does not equal 0,
so we can see that (1,0) is NOT the option we're looking for.

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Write an equivalent expression for 36 divided by [-9] [-5]?

natima [27]

36/-9-5=14/7-11 36/-9=-4 -4-5=-9 14/7=2 2-11=-9

3 0

3 years ago

HELP!! What is the absolute value of –1.9?

natka813 [3]

Answer:

1.9

Step-by-step explanation:

numbers in an absolute value sign are always positive.

3 0

3 years ago

Read 2 more answers

Bananas cost $1.15 per pound. Jose bought 2.4 pounds of bananas. How much did it cost?

Serggg [28]

Answer:

$ 2.76

Step-by-step explanation:

Hi there !

1 pd ........... $1.15

2.4pd .........$ x

x = 2.4×1.15/1

= $ 2.76

Good luck !

4 0

3 years ago

5. The superintendent of the local school district claims that the children in her district are brighter, on average, than the g

anygoal [31]

Answer:

We conclude that children in district are brighter, on average, than the general population.

Step-by-step explanation:

We are given the following data set:

105, 109, 115, 112, 124, 115, 103, 110, 125, 99

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1117}{10} = 111.7$

Sum of squares of differences = 642.1

$S.D = \sqrt{\frac{642.1}{49}} = 8.44$

We are given the following in the question:

Population mean, μ = 106

Sample mean, $\bar{x}$ = 111.7

Sample size, n = 10

Alpha, α = 0.05

Sample standard deviation, s = 8.44

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 106\\H_A: \mu > 106$

We use one-tailed(right) t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{111.7 - 106}{\frac{8.44}{\sqrt{10}} } = 2.135$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = 1.833$

Since,

$t_{stat} > t_{critical}$

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

We conclude that children in district are brighter, on average, than the general population.

4 0

3 years ago

Mr.Johnson weighs 135 pounds. Her husband weighs 80 kilogram. How many fewer pounds does Ms.Johnson weigh than her husband?

sweet-ann [11.9K]

First you convert kilograms to pounds,
1 kilogram = 2.205 pounds
next you times the number of pounds per kilogram by the number of kilograms given that need to be turned into pounds.
80 times 2.205 = 176.4
next you subtract to get the answer
176.4 - 135= 41.4
so Ms. Johnson weighs 41.4 pounds less than herr husband

3 0

3 years ago