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Komok [63]
4 years ago
13

Im really confused on this one

Mathematics
2 answers:
V125BC [204]4 years ago
7 0

Answer:

ill try

Step-by-step explanation:

n is the number so n= 2-11 and so on

kenny6666 [7]4 years ago
7 0

Answer:

B

Step-by-step explanation:

First do the distributive property of 2(1 - 4n) so

3n + 2(1 - 4n)

3n + 2 - 8n <u>Now add or subtract the like terms.</u>

-5n + 2

2 - 5n

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A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar
ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let \mu = <u><em>mean waiting time for bus number 14.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 10 minutes      {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, H_A : \mu < 10 minutes    {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 7.8 minutes

             s = sample standard deviation = 2.5 minutes

             n = sample of different occasions = 18

So, <u><em>test statistics</em></u> =  \frac{7.8-10}{\frac{2.5}{\sqrt{18} } }  ~ t_1_7

                              =  -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST
Dovator [93]
The second one is right
8 0
3 years ago
Solve the simultaneous equations: <br> 5x + 2y = 17<br> 4x + y = 10
erik [133]

Answer:

(1, 6 )

Step-by-step explanation:

5x + 2y = 17 → (1)

4x + y = 10 → (2)

Multiplying (2) by - 2 and adding to (1) will eliminate the y- term

- 8x - 2y = - 20 → (3)

Add (1) and (3) term by term to eliminate y

- 3x + 0 = - 3

- 3x = - 3 ( divide both sides by - 3 )

x = 1

Substitute x = 1 into either of the 2 equations and solve for x

Substituting into (1)

5(1) + 2y = 17

5 + 2y = 17 ( subtract 5 from both sides )

2y = 12 ( divide both sides by 2 )

y = 6

solution is (1, 6 )

8 0
2 years ago
What's 65.247 rounded to the nearest tenth
jek_recluse [69]

Answer:

65.2

Step-by-step explanation:

the two is the tenth and your not adding any thing because the 4 is less than five

5 0
3 years ago
A survey found that women's heights are normally distributed with mean 62.7 in, and standard deviation 2.8 in. The survey also f
Viefleur [7K]

Using the normal distribution, we have that:

The percentage of men who meet the height requirement is 3.06%. This suggests that the majority of employees at the park are females.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation of men's heights are given as follows:

\mu = 69.3, \sigma = 3.9.

The proportion of men who meet the height requirement is is the <u>p-value of Z when X = 62 subtracted by the p-value of Z when X = 55</u>, hence:

X = 62:

Z = \frac{X - \mu}{\sigma}

Z = \frac{62 - 69.3}{3.9}

Z = -1.87

Z = -1.87 has a p-value of 0.0307.

X = 55:

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 69.3}{3.9}

Z = -3.67

Z = -3.67 has a p-value of 0.0001.

0.0307 - 0.0001 = 0.0306 = 3.06%.

The percentage of men who meet the height requirement is 3.06%. This suggests that the majority of employees at the park are females.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0
1 year ago
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