The first figure is dilated to form the second figure.
1 answer:
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The mean of the sample given by 44,22,11,17,21 will be given by:
the sum of x's will be:
44+22+11+17+21
=115
n=5
therefore the mean will be:
μ=115/5
=23
the sum of x's will be:
44+22+11+17+21
=115
n=5
therefore the mean will be:
μ=115/5
=23