V=s/t
s=300 km = 300000 m
t=1 h and 30 min = 5400 sec
v=300/1,5= 200 km/h
or
v=300000/5400=55,5 m/s
Answer:
yes it's true.
Step-by-step explanation:
if angle G is congruent to angle H then angle H is also congruent to angle G
Answer:
4 x^3 - 3 x^2
Step-by-step explanation:
Expand the following:
x^2 (4 x - 3)
x^2 (4 x - 3) = x^2×4 x + x^2 (-3):
4 x^2 x - 3 x^2
x^2×4 x = x^(2 + 1)×4:
4 x^(2 + 1) - 3 x^2
2 + 1 = 3:
Answer: 4 x^3 - 3 x^2
<h3>Answer: choice A) </h3><h3>tan(Y) = 6/7 and tan(Z) = 7/6</h3>
Recall that the tangent of an angle is equal to the ratio of the opposite over adjacent sides
tan(angle) = opposite/adjacent
For reference angle Y, the opposite side is XZ = 6 and the adjacent side is XY = 7, so,
tan(Y) = XZ/XY = 6/7
For tan(Z), things will swap. The opposite side is now XY = 7 and the adjacent side is now XZ = 6
tan(Z) = XY/XZ = 7/6
We do not use the hypotenuse sqrt(85) at all in this problem because the tangent ratio does not involve the hypotenuse.
Answer: See below
Step-by-step explanation:
27. -(a-3)
28. (b-1)(b+3)
29. (c+4)(c+5)
30. d(d+5)
31. -(3/4)(2e-5)
Sorry - I don't have time to enter the details. Look for areas where the expressions can be factored in a manner that forms as many equivalent expressions in both the numerator and denominator.
For example: In problem 30:
(5d-20)/(d^2+d-20) * [??]/20d = 1/4
Factor:
<u>(5(d-4))</u> <u>d(d+5)</u> = 1/4
(d-4)(d+5<u>)</u> 20d
The (d-4), d+5, and d terms cancel, leaving
5/20 = 1/4
