Step-by-step explanation:
Datos;
una locomotora
recorre 5 horas
a una velocidad de 82 km/h
Se asume que la locomotora lleva un movimiento rectilíneo uniforme.
Su recorrido esta descrito por la siguiente ecuación de posición;
x = x₀+ v · t
x-x₀ = d = v · t
siendo;
d = distancia recorrida
v = 82 km/h
t = 5 horas
Sustituir:
d = (82)(5)
d = 410 km
82km/h * 5h= 410km
La locomotora recorrerá 410km
<h3>Given</h3>
A(-3, 1), B(4, 5)
<h3>Find</h3>
coordinates of P on AB such that AP/PB = 5/2
<h3>Solution</h3>
AP/PB = 5/2 . . . . . desired result
2AP = 5PB . . . . . . multiply by 2PB
2(P-A) = 5(B-P) . . . meaning of the above
2P -2A = 5B -5P . . eliminate parentheses
7P = 2A +5B . . . . . collect P terms
P = (2A +5B)/7 . . . .divide by the coefficient of P
P = (2(-3, 1) +5(4, 5))/7 . . . . substitute the given points
P = (-6+20, 2+25)/7 . . . . . . simplify
P = (2, 3 6/7)
Answer:
5
Step-by-step explanation:
The function
is
- decreasing for all

- is increasing for all
![x\in (0,2]](https://tex.z-dn.net/?f=x%5Cin%20%280%2C2%5D)
(see attached diagram for details).
The maximum value of the function is at endpoints -3 or 2. find y(-3) and y(2):

So, the maximum value is 5.
Answer:
x= -0.94 repeating
Step-by-step explanation:
hope this helps