Question

The complex solution to a quadratic equation is x equals start fraction three plus or minus square root of negative 36 end square root over six end fraction full stop Write this solution in standard form, a + bi, where a and b are real numbers. What are the values of a and b?

Answer 1

The square root of a -36 simplifies to "6i". So you have 3+/- [6i/6].  The 6's cancel each other out leaving 3+/-i.  So the "a" is 3 and the "b" is 1