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STatiana [176]
3 years ago
10

The complex solution to a quadratic equation is x equals start fraction three plus or minus square root of negative 36 end squar

e root over six end fraction full stop Write this solution in standard form, a + bi, where a and b are real numbers. What are the values of a and b?
Mathematics
1 answer:
Naya [18.7K]3 years ago
4 0
The square root of a -36 simplifies to "6i". So you have 3+/- [6i/6].  The 6's cancel each other out leaving 3+/-i.  So the "a" is 3 and the "b" is 1
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==================
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