Solution:
It is given that two triangles Δ ABC and Δ X Y Z are similar by Side -Side - Side(SSS) Similarity theorem.
So, the Statement which is given, that is →→∠B ≅ ∠Y and ∠B ≅ ∠Z, is inadequate for similarity criterion by SSS, as these statement are about angles of Triangles,not sides, which can't be true.
So, if the two triangles are Similar by SSS criterion , then the appropriate mathematical statement must be,
⇒
D (0, -3)
E (1, 0)
F (2, -1)
<h3>
Answer: 8/25</h3>
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Explanation:
In a standard deck, there are 52 cards.
If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.
There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.
Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.
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The event space has A = 16 cards in it, while the sample space has B = 50 cards.
The probability we're after is A/B = 16/50 = 8/25
Answer: 1 and 4 are correct
Step-by-step explanation: good luck!
