POH = - log [ OH⁻ ]
pOH = - log [ 1 x 10⁻⁹ ]
pOH = 9
Answer C
hope this helps!
Answer:
a substance that dissolves in another substance
Explanation:
a substance into which another substance dissolves
Is that supposed to say 200/2.00??
Answer:
CO₂. Option B.
Explanation:
We can use the Ideal Gases Law to solve this question
Formula: P . V = n. R . T
First of all, we convert the T° from °C to K
T°C + 273 → 0°C + 273 = 273K
Let's replace data: 15 atm . 0.7462 L = n . 0.082 L.atm/mol.K . 273K
15 atm . 0.7462 L / (0.082 L.atm/mol.K . 273K) = n
0.500 mol = n
These moles are the amount for 22 g of gas. Let's determine the molar mass to find out the gas → molar mass = g/mol
22 g /0.5m = 44g/mol
This molar mass corresponds to CO₂
