The line y = x + 3 has slope 1, so we look for points on the curve where the tangent line, whose slope is dy/dx, is equal to 1.
y² = x
Take the derivative of both sides with respect to x, assuming y = y(x) :
2y dy/dx = 1
dy/dx = 1/(2y)
Solve for y when dy/dx = 1 :
1 = 1/(2y)
2y = 1
y = 1/2
When y = 1/2, we have x = y² = (1/2)² = 1/4. However, for the given line, when y = 1/2, we have x = y - 3 = 1/2 - 3 = -5/2.
This means the line y = x + 3 is not a tangent to the curve y² = x. In fact, the line never even touches y² = x :
x = y² ⇒ y = y² + 3 ⇒ y² - y + 3 = 0
has no real solution for y.
Answer:
7(88)=616
Step-by-step explanation:
For the first 3 you just have to divide (forget about the square root for now) and then reduce its result by finding two numbers (one of them have to be able to be squared rotted) that multiplied gives the fist result. Then you just have to square root one of the numbers and leave the other one as it is.
For the last 4; you cannot have radicals in the denominator, so you have to multiply both top and bottom by the square root, after that you just reduce.
Hope you understand, if you have any questions please let me know.
Comparing the cost of the car to the deposit, $3,168.00 the amount required to be added to the deposit
$3,168 is the interest
rate = 8%
time = T
principal = 6,600.00
I = ( PRT)/100
T = 100 I/PR
=(100*3168)/(6600*8)
= 6
She should leave the money for six years.