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antiseptic1488 [7]
2 years ago
6

Suppose the Random Selection of Letters were repeated. Do you think that the ratios would be the same? Explain.

Mathematics
1 answer:
vfiekz [6]2 years ago
8 0
A probability p that an experiment will result in outcome A, then if we repeat this ... each integer has the same probability of being chosen. ... computer toss a coin, we can ask it to pick a random real number in the ... The famous letters between Pas- ..... for four tosses, and see if you think that these probabilities are, in fact, the.
You might be interested in
Which of the following is most likely the next step in the series?
Nostrana [21]

Answer:

A is most likely the next step in the series

Step-by-step explanation:

Each step, the number of sides is increasing by 1.

4,5,6 means that the next number of sides would be 7. Option A has 7 sides.

8 0
2 years ago
What’s the volume of a cylinder with a radius of 1 and height of 3ft?
Dafna1 [17]

Answer:

9.42

Step-by-step explanation:

V=pir2h

(pi, radius squared, height)

hope this helped!

6 0
2 years ago
Please please please help me!
OleMash [197]

Answer:

<76

Step-by-step explanation:

Remark

You can't do this problem unless CD and E are all on the same line. If they are, then you can use || line properties.

Properties

<ABG = x                       Given

<ABG = <BGF               Alternate interior angles are equal.

<BGF = x                       Substitute

x + 2x - 9 = 180             Consecutive angles in a ||gram equal 180 degrees.

3x - 9 = 180                    Add 9 to both sides

3x - 9 +9 = 180 +9

3x = 189                         Divide by 3

x = 63

<DHG = 2x - 50            Given

<DHG = 2*63 - 50         Substitute for x

<DHG = 76

<IDC  = 76

<DHG and <IDC are corresponding angles and are equal; it is a property of parallel lines.

6 0
3 years ago
Find the volume of the pyramid.
lana66690 [7]

Answer:

140

Step-by-step explanation:

B=35

1/3 (35)(12)

= 140

6 0
3 years ago
Hey!
noname [10]

Answer:

A. Cylinder + cone

<u>Volume is the sum of volumes:</u>

  • V = Vcon + Vcyl = 1/3πr²h₁ + πr²h₂
  • V = 1/3π*9²*12 + π*9²*120 = 31554.2 cm³

<u>Surface area of cone:</u>

  • A = A=πr(r+√(h₁²+r²)) = π*9(9 + √(9²+12²)) = 678.6 cm²

<u>Surface area of cylinder minus bases:</u>

  • A = 2πrh₂ = 2π*9*120 = 6785.8 cm²

<u>Total surface area:</u>

  • 678.6 + 6785.8 = 7464.4 cm²

-------------------------------------------------

B. Cube+ pyramid

<u>Volume:</u>

  • V = a³ + (1/3)a²h = a³ + (1/3)a²√(l²-(a/2)²)
  • V = 8³ + (1/3)8²√(10²-4²) = 707.5 cm³

<u>Surface area of pyramid:</u>

  • A = a² + 2al = 8² + 2*8*10 = 224 cm²

<u>Surface area of cube minus bases:</u>

  • A = 4a² = 4(8²) = 256 cm²

<u>Total surface area:</u>

  • A = 224 + 256 = 480 cm²
5 0
3 years ago
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