Answer:
No
Step-by-step explanation:
Complex answer: For a point to be in quadrant II, it must have a negative x value and a positive y value.
Simple answer: The 1 would have to be negative to be in quadrant II, and it isn't
If you go on my profile you will see a similar problem that I already answered today.
Lets start by using a formula (don't remember the name)
(y-y1)=M(x-x1)
M is slope and y is first y value and y1 is second y value same applies to X.
Substitute in the values.
(5-q) = 10(-6-(-7))
5-q = 10*(1)
5-q = 10
-q = 5
q = -5
Check:
Substitute in the value of "q" and use the formula to find slope:
(y1-y)/(x1-x)
Substitute
(-5-5)/(-7-(-6))
-10/-1
10
Your Answer:
The value of "q" is -5
Answer:
true duhh :))
Step-by-step explanation:
Answer:
48
Step-by-step explanation:
