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podryga [215]
2 years ago
13

These 12 shapes are put into a bag. If you reach

Mathematics
1 answer:
Svetlanka [38]2 years ago
3 0
25 times :) hope this helped!
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Solve the solution of a system of linear equation<br><br> 1/2 x + y = - 6<br> 6 x + 2 y = 8
Lilit [14]

Answer:

(4,-8)

Step-by-step explanation:

Plug in the answers for the equations.

4 0
3 years ago
The graph below represents the amount of change Jaxon would receive, y, if he bought a item with a cost of x.
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Answer:

I don't really understand the question

Step-by-step explanation:

I don't know the answer

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3 years ago
Compute the probability of randomly selecting a three or club.
Pavlova-9 [17]
Find the total number of cards in a deck. Count all the # 3’s total cards/#3 cards
Count all the clubs total card/ clubs
Not sure if you are counting 3’s & clubs together. If you are, total cards/ both
So all you have to do is count & then divide to get the probability.
5 0
2 years ago
Pentagon PQRST and its reflection, pentagon P'Q'R'S'T', are shown in the coordinate plane below.
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5 0
3 years ago
What is the square root of m^6?
Nastasia [14]
Answer:
If m is nonnegative (ie not allowed to be negative), then the answer is m^3
If m is allowed to be negative, then the answer is either |m^3| or |m|^3

==============================

Explanation:

There are two ways to get this answer. The quickest is to simply divide the exponent 6 by 2 to get 6/2 = 3. This value of 3 is the final exponent over the base m. Why do we divide by 2? Because the square root is the same as having an exponent of 1/2 = 0.5, so
sqrt(m^6) = (m^6)^(1/2) = m^(6*1/2) = m^(6/2) = m^3
This assumes that m is nonnegative. 

---------------------------

A slightly longer method is to break up the square root into factors of m^2 each and then apply the rule that sqrt(x^2) = x, where x is nonnegative

sqrt(m^6) = sqrt(m^2*m^2*m^2)
sqrt(m^6) = sqrt(m^2)*sqrt(m^2)*sqrt(m^2)
sqrt(m^6) = m*m*m
sqrt(m^6) = m^3
where m is nonnegative

------------------------------

If we allow m to be negative, then the final result would be either |m^3| or |m|^3. 

The reason for the absolute value is to ensure that the expression m^3 is nonnegative. Keep in mind that m^6 is always nonnegative, so sqrt(m^6) is also always nonnegative. In order for sqrt(m^6) = m^3 to be true, the right side must be nonnegative.

Example: Let's say m = -2
m^6 = (-2)^6 = 64
sqrt(m^6) = sqrt(64) = 8
m^3 = (-2)^3 = -8
Without the absolute value, sqrt(m^6) = m^3 is false when m = -2

4 0
3 years ago
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