Answer:
No , we would not reject the null hypothesis at α = 0.05
Step-by-step explanation:
Given that a random survey of 100 students asked each student to select the most preferred form of recreational activity from five choices. Following are the results of the survey.
(Two tailed chi square test at 5% level for testing independence between gender and sports activities)
We assume H0 to be true and prepare expected values and then calculate chi square as (O-E)^2/E where O = observed value, E = expected value
Basketball Softball Swimming running Tennis
Males 21 (18.00) [0.50] 5 (4.80) [0.01] 9 (6.00) [1.50] 12 (16.20) [1.09] 13 (15.00) [0.27] 60
Females 9 (12.00) [0.75] 3 (3.20) [0.01] 1 (4.00) [2.25] 15 (10.80) [1.63] 12 (10.00) [0.40] 40
chisquare 8.4097
p value 0.077
df 4
Since p > 5% we accept null hypothesis.
No , we would not reject the null hypothesis at α = 0.05
The function represents the number of accidents (f(x)) per 50 million miles driven as a function of the driver's age (x).
f(45) indicates that you have to find the value of f(x) when x=45, to do so replace the equation of the function with the value of x and solve for f(x)
For x=45 years f(x)=190
f(45)=190; This value indicates that 45-year-old drivers had 190 accidents per 50 million miles driven.