Question

A 20.6 g marble sliding to the right at 59.6 cm/s overtakes and collides elastically with a 10.3 g marble moving in the same direction at 14.9 cm/s. After the collision, the 10.3 g marble moves to the right at 74.5 cm/s. Find the velocity of the 20.6 g marble after the collision.

Answer 1

Answer:29.8 cm/s

Explanation:

Given

mass of marble A is $m_a=20.6\ gm$

Initial velocity of marble A is $u_a=59.6\ cm/s$

mass of marble B is $m_b=10.3\ gm$

Initial velocity of marble B $u_b=14.9\ cm/s$

After collision marble B moves with velocity of $v_b=74.5\ cm/s$

Conserving momentum

$m_au_a+m_bu_b=m_av_a+m_bv_b$

$20.6\times 59.6+10.3\times 14.9=20.6\times v_a+10.3\times 74.5$

$v_a=\frac{20.6\times 59.6-10.3(74.5-14.9)}{20.6}$

$v_a=29.8\ cm/s$