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4 years ago

Which meter, ammeter or the voltmeter, has the higher internal resistance? why does this make sense?

Physics

1 answer:

kodGreya [7K]4 years ago

8 0

Answer:

Voltmeter

Explanation:

A voltmeter is usually defined as an instrument that is commonly used to measure the electric potential difference acting between the two ends of a circuit. The unit of voltmeter is volts. Here, connections are made in parallel arrangement.

An ammeter is a device that is commonly used to measure the amount of flowing current within a circuit. The unit of current is in terms of amperes (A). Here, connections are made in series.

A voltmeter is usually comprised of high internal resistance in comparison to an ammeter because a high internal resistance results in the heating up of the battery and subsequent dropping its voltage and after the equipments are being cuts off, it leaves behind certain amount of energy.

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A fly flaps its wings back and forth 25 times in one second. The period of wing flapping is _____.

dalvyx [7]

Answer:

<h2>The period is 0.04 sec</h2>

Explanation:

This problem is based on oscillatory motion.

What is the period of oscillation?

This can be defined as the time taken to complete one full revolution or oscillation.

given that the fly flaps its wings back and forth 25 times in one second. then the frequency is 25 Hz

we know that period T= 1/F

T= 1/25

T=0.04 sec

3 0

3 years ago

Suppose a vertebra is subjected to a shearing force of 420 N. Find the shear deformation in m, taking the vertebra to be a cylin

vazorg [7]

Answer:

$1.34103\times 10^{-7}\ m$

Explanation:

F = Shearing force = 420 N

$L_0$ = Initial length = 2.6 cm

d = Diameter = 3.6 cm

r = Radius = $\frac{d}{2}=\frac{3.6}{2}=1.8\ cm$

E = Young's modulus = $80\times 10^9\ N/m^2$

A = Area = $\pi r^2$

Change in length is given by

$\Delta L=\frac{FL_0}{AE}\\\Rightarrow \\\Rightarrow \Delta L=\frac{420\times 0.026}{\pi 0.018^2\times 80\times 10^9}\\\Rightarrow \Delta L=1.34103\times 10^{-7}\ m$

The shear deformation of the vertebra is $1.34103\times 10^{-7}\ m$

8 0

3 years ago

True or false. A solvent is the part of a solution that dissolves the solute

mash [69]

Answer:

True

Explanation:

I'm not exactly sure on this , but A solution is made up of two components. Namely,

1. The solvent

2. The solute

The solute has a lower percentage in the solution while the solvent has a higher percentage in the solution so yes, the solvent is used to dissolve the solute

6 0

3 years ago

If the Hubble Space Telescope is 598 m above the surface of the Earth and is traveling at 7.56 x 103 m/s, how long does it take

viva [34]

Answer:

5069.04 seconds

Explanation:

The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.

It is given as:

$T = \sqrt{\frac{4\pi^2r^3 }{GM} }$

where r = radius of orbit of Hubble Space Telescope

G = gravitational constant = $6.67408 * 10^{-11} m^3 kg^{-1} s^{-2}$

M = Mass of earth

We are given that:

r = radius of the earth + distance of HST from earth

r = $6.38 * 10^6 + 598 = 6380598 m$

M = $5.98 * 10^{24} kg$

Therefore, T will be:

$T = \sqrt{\frac{4*\pi^2 * 6380598^3 }{6.67408 * 10^{-11} * 5.98 * 10^{24}}}$

$T = 5069.04 secs$

The orbital period of the Hubble Space Telescope is 5069.04 seconds.

7 0

3 years ago

Read 2 more answers

A helicopter, starting from rest, accelerates straight up from the roof of a hospital. The lifting force does work in raising th

Whitepunk [10]

Answer:

24.3KW

Explanation:

A)The kinetic energy is changing, the potential energy is changing and the chemical energy in form of fuel powering the engine also is changing

The kinetic energy is increasing as the body gain speed, the potential energy also increases as the body gain height against gravity and the chemical energy in form of fuel decreases as the body burn the fuel to create a lifting force

B) The workdone by the lifting force = the change in kinetic energy + the change in potential energy

C)The time taken in seconds to do the work is the variable needed

D) average power generated by the lifting force = (change in kinetic energy + change in potential energy) / time taken in seconds

Average power = 1/2 * m(mass) (Vf-Vi)^2 + mg(hf-hi) /t where vf is final speed and vi is initial speed at rest = 0, similarly, hf = final height and hi = initial height.

Average power = 1/2*810*7^2 + 810*9.81*8.2/3.5s

Average power = (19845+65158.02)/3.5 = 24286.577 approx 24.3kW

5 0

3 years ago