MaCa∆Tb = MbC∆Tb
Where
m is the mass of a compound
<span>
C
is the specific heat of a compound
</span>∆T is the change of temperature of the compound
<span>
(0.502
kg water)(4180 j/kg C)( 28.6 – 22 C) = ( 0.145 kg tungsten) ( C ) ( 130 – 28.6
C)
</span>Solve
for C
<span>C
= 941.9 J /kg C </span>
Answer:
3,333.33 /sec
Explanation:
frequency = 1/period
= 1/0.0003 = 3,333.33 /sec
Answer:
B. Bend away from each other
Explanation:
In scientific notation", that number would be written as
6.81 x 10⁻⁴ .
