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qwelly [4]
2 years ago
7

Help please ! Ill give brainliest !! ☁️✨

Physics
1 answer:
KATRIN_1 [288]2 years ago
3 0
Answer:
Force Meter > used to measure force
Milli > Prefix that means 1/1,000
Centi > Prefix that means 1/100
Kilo > Prefixes that means 1,000
Thermometer > used to measure Temperature


Explanation: uh just trust
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a farmer lifts a bale of hay that is 12m off the ground . If he uses a force of 350 n, how much work does the farmer do?
hjlf

Answer:

4200 Joules

Explanation:

Work done =force x distance

From the question , we’re given f =350N ,

d = 12m

Using the above formula, we have

Workdone = 350 x 12

= 4200 Joules

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3 years ago
A calcium-40 ion has a positive charge that is double the charge of a proton, and a mass of 6.64 ✕ 10−26 kg. At a particular ins
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Detailed solution is given below

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Which statement describes how the atoms in a conducting wire are organized?(1 point)
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Positively charged nuclei are packed in an organized pattern, and the negatively charged valence electrons flow freely.

Explanation:

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A particle initially located at the origin has an acceleration of a=3jm/s^2 and an initial velocity of Vi=5im/s.
-BARSIC- [3]

Given the particle's acceleration is

\vec a(t) = \left(3\dfrac{\rm m}{\mathrm s^2}\right)\vec\jmath

with initial velocity

\vec v(0) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath

and starting at the origin, so that

\vec r(0) = \vec 0

you can compute the velocity and position functions by applying the fundamental theorem of calculus:

\vec v(t) = \vec v(0) + \displaystyle \int_0^t \vec a(u)\,\mathrm du

\vec r(t) = \vec r(0) + \displaystyle \int_0^t \vec v(u)\,\mathrm du

We have

• velocity at time <em>t</em> :

\vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \displaystyle \int_0^t \left(3\dfrac{\rm m}{\mathrm s^2}\right)\,\vec\jmath\,\mathrm du \\\\ \vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath \\\\ \boxed{\vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath}

• position at time <em>t</em> :

\vec r(t) = \displaystyle \int_0^t \left(\left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)u\,\vec\jmath\right) \,\mathrm du \\\\ \boxed{\vec r(t) = \left(5\dfrac{\rm m}{\rm s}\right)t\,\vec\imath + \frac12 \left(3\frac{\rm m}{\mathrm s^2}\right)t^2\,\vec\jmath}

8 0
3 years ago
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