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3 years ago

Given given the formula for the compound: This compound is classified as an...

Chemistry

1 answer:

nalin [4]3 years ago

6 0

Answer:

Option 3. alkyne

Explanation:

The aldehydes are organic compounds with the functional group -CHO attached to parent chain it can be written as R-CHO where R is an alkyl group.

The alkenes are generally unsaturated hydrocarbon with a carbon to carbon double bond

(-C=C-) attached the parent chain.

The alkynes are unsaturated hydrocarbon with a carbon to carbon triple bond (-C≡C-) attached to the parent chain.

Alcohols are organic compounds with the functional group -OH attached to the parent chain. It can be written as R-OH where R is an alkyl group.

From the brief explanation above, the answer to the question is alkyne because the diagram has carbon to carbon triple bond (-C≡C-) attached to the parent chain.

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Please help find Empirical formula! :)

mamaluj [8]

Answer:

The empirical formula of a compound is the simplest whole number ratio of each type of atom in a compound. It can be the same as the compound's molecular formula, but not always. An empirical formula can be calculated from information about the mass of each element in a compound or from the percentage composition

Explanatio internet bud

8 0

3 years ago

Carbon-14 is a radioactive isotope that decays according to first-order kinetics in a process that has a half-life of 5730 years

Sliva [168]

Answer : The time passed in years is $2.83\times 10^3\text{ years}$

Explanation :

Half-life = 5730 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{5730\text{ years}}$

$k=1.21\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $1.21\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = ?

a = let initial amount of the reactant = X g

a - x = amount left after decay process = $71\% \times (x)=\frac{71}{100}\times (X)=0.71Xg$

Now put all the given values in above equation, we get

$t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{X}{0.71X}$

$t=2831.00\text{ years}=2.83\times 10^3\text{ years}$

Therefore, the time passed in years is $2.83\times 10^3\text{ years}$

8 0

3 years ago

A radioactive isotope of potassium (k) has a half-life of 20 minutes. if a 43 gram sample of this isotope is allowed to decay fo

Ksenya-84 [330]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 43 g

m (final mass after time T) = ? (in g)

x (number of periods elapsed) = ?

P (Half-life) = 20 minutes

T (Elapsed time for sample reduction) = 80 minutes

Let's find the number of periods elapsed (x), let us see:

$T = x*P$

$80 = x*20$

$80 = 20\:x$

$20\:x = 80$

$x = \dfrac{80}{20}$

$\boxed{x = 4}$

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

$m = \dfrac{m_o}{2^x}$

$m = \dfrac{43}{2^{4}}$

$m = \dfrac{43}{16}$

$\boxed{\boxed{m = 2.6875\:g}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR! =)

8 0

4 years ago

What is the major distinguishing factor between ionic/covalent bonding and intermolecular forces? a. Intermolecular forces are m

IceJOKER [234]

The answer is C. Ionic and covalent bonding exists in the same compound and intermolecular forces exist between different compounds. And that is way called intermolecular forces.

3 0

3 years ago

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