Answer and Explanation:
A ionic compound can be dissociated into its ions: <em>cations</em> (with positive charge) and <em>anions</em> (with negative charge). The net charge of the compound is zero, so the sum of the charges of the ions must be zero.
We can see the ions in the compounds from the dissociation equilibrium, as follows:
a) NaBr ⇒ Na⁺ + Br⁻
Cation: Na⁺
Anion: Br⁻ (bromide)
b) AlCI₃ ⇒ Al³⁺ + 3 Cl⁻
Cation: Al³⁺
Anion: Cl⁻ (chloride)
c) Ba₃(PO₄)₂⇒ 3 Ba²⁺ + 2 PO₄³⁻
Cation: Ba²⁺
Anion: PO₄³⁻ (phosphate)
d) Mn(NO₃)₂ ⇒ Mn²⁺ + 2 NO₃⁻
Cation: Mn²⁺
Anion: NO₃⁻ (nitrate)
Answer: Option (b) is the right answer.
Explanation:
The beaker on the left shows that atoms are at rest it means they don't have any kinetic energy. Hence, atoms are lying at the bottom of the beaker. Since the molecules or atoms are not enclosed in a definite shape therefore, they are in liquid state.
The beaker on the right shows that atoms are far apart from each other therefore, the atoms have kinetic energy due to which they are able to move randomly. Only in a gaseous state the atoms or molecules can move far apart from each other.
Thus, we can conclude that the atoms gain energy as a liquid changes to a gas.
Copper has a FCC i.e. face centered cubic crystal structure. The 100 plane is essentially a planar section of the cubic cell where 4 Cu atoms occupy the 4 corners of the plane along with 1 Cu atom at the center of that plane. Each of the Cu atoms in the corners is shared by 4 adjacent unit cells. Thus, there are 2 Cu atoms present in the 100 plane (4*1/4 + 1 = 2).
Now, the planar density PD along the 100 plane is given as:
PD(100) = # atoms in the 100 plane/Area of 100 plane
=
Here R = radius = 0.128 nm =
PD =
Answer:
26.20% w/w of KBr in the sample
Explanation:
Mohr titration is a way to quantify Br⁻ and Cl⁻ ions in solution. The reaction is:
KBr(aq) + AgNO₃(aq) → KNO₃(aq) + AgBr(s)
<em>where 1 mole of KBr reacts per mole of AgNO₃</em>
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Thus, moles of AgNO₃ in (25.13mL-0.65mL = 24.48mL) of a 0.04614M solution are:
0.02448L × (0.04614mol / L) = 1.130x10⁻³ moles of AgNO₃ = moles of KBr.
Mass of KBr -Molar mass: 119g/mol- is:
1.130x10⁻³ moles of KBr × (119g / 1mol) = <em>0.1344g of KBr</em>
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Thus, %w/w of KBr in the sample is:
%w/w = 0.1344g / 0.5131g ×100 = <em>26.20% w/w of KBr in the sample</em>