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IrinaK [193]
3 years ago
8

CH3CO2H(aq) + H2O(l) ⇄ CH3CO2-(aq) + H3O+(l)

Chemistry
1 answer:
Evgen [1.6K]3 years ago
4 0
Correct Answer: Option C:<span> The equilibrium position will shift to the right toward the products. 

Reason:
1) This problem is based on </span>Le Chatelier's principle. It is stated as '<em>any</em><span><em> changes in the temperature, volume, or concentration of a system will result in predictable and opposing changes in the system in order minimize this change and achieve a new equilibrium state.</em>' 

2) In present case, the reaction involved is: 
</span><span>                 CH3CO2H(aq) + H2O(l) ⇄ CH3CO2-(aq) + H3O+(l) 
</span>Hence, when the concentration of acetic acid (reactant) is increased, the equilibrium will shift to right to minimize the effect of change in concentration of reactant. 
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2 years ago
Why don't we discuss the results during the results section of the project?
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Explanation:

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3 years ago
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Does wasting water also waste energy? Explain your reasoning.
77julia77 [94]

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6 0
3 years ago
Read 2 more answers
A 1.59 mol sample of Kr has a volume of 641 mL. How many moles of Kr are in a 4.41 L sample at the same temperature and pressure
Marina86 [1]

Answer:

The correct answer is 10.939 mol ≅ 10.94 mol

Explanation:

According to Avogadro's gases law, the number of moles of an ideal gas (n) at constant pressure and temperature, is directly proportional to the volume (V).

For the initial gas (1), we have:

n₁= 1.59 mol

V₁= 641 mL= 0.641 L

For the final gas (2), we have:

V₂: 4.41 L

The relation between 1 and 2 is given by:

n₁/V₁ = n₂/V₂

We calculate n₂ as follows:

n₂= (n₁/V₁) x V₂ = (1.59 mol/0.641 L) x 4.41 L = 10.939 mol ≅ 10.94 mol

5 0
2 years ago
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