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IrinaK [193]
3 years ago
8

CH3CO2H(aq) + H2O(l) ⇄ CH3CO2-(aq) + H3O+(l)

Chemistry
1 answer:
Evgen [1.6K]3 years ago
4 0
Correct Answer: Option C:<span> The equilibrium position will shift to the right toward the products. 

Reason:
1) This problem is based on </span>Le Chatelier's principle. It is stated as '<em>any</em><span><em> changes in the temperature, volume, or concentration of a system will result in predictable and opposing changes in the system in order minimize this change and achieve a new equilibrium state.</em>' 

2) In present case, the reaction involved is: 
</span><span>                 CH3CO2H(aq) + H2O(l) ⇄ CH3CO2-(aq) + H3O+(l) 
</span>Hence, when the concentration of acetic acid (reactant) is increased, the equilibrium will shift to right to minimize the effect of change in concentration of reactant. 
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Read 2 more answers
Why is the concentration of 1.34gvCuCl2 in a volumetric flask with approx. 100mL of water has a concentration of 0.050M?
jarptica [38.1K]
<h3>Answer:</h3>

Concentration will be 0.1 M and not 0.050M

<h3>Explanation:</h3>

This explains why the molarity is not 0.050 M but 0.1 M

Molarity is the concentration of a solution in moles per liter.

Therefore,

Molarity = moles ÷ Volume

In this case,

We have 1.34 g of CuCl₂ and a volume of 100 mL

To get the molarity we need to find the number of moles in 1.34 CuCl₂

Number of moles = Mass÷ molar mass

Molar mass of CuCl₂ = 134.45 g/mol

Therefore,

Moles of CuCl₂ = 1.34 g ÷ 134.45 g/mol

                         = 0.009965 moles

                         = 0.01 moles

Then we can calculate the molarity;

Molarity = Number of moles ÷ Volume

Volume of the solution is 100 mL or 0.1 L

Molarity = 0.01 moles ÷ 0.1 L

            = 0.1 M

Therefore, the concentration of 1.34 g CuCl₂ in a volume of 100 mL is 0.1 M and not 0.050M.

8 0
3 years ago
Select all that apply.
tekilochka [14]
Answer is:<span>increase [Cl</span>₂<span>] and remove HCl from the product.
</span>Chemical reaction: Cl₂ + CH₂Cl₂ → CHCl₃(chloroform) + HCl.
According to Le Chatelier's Principle, the position of equilibrium moves to counteract the change, the position of equilibrium will move so that the concentration of reactants decrease (Cl₂) and concentration of products of chemical reaction increase (CHCl₃) if increase concentration of reactants and decrease concentration of products.

 


3 0
3 years ago
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