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IrinaK [193]
2 years ago
8

CH3CO2H(aq) + H2O(l) ⇄ CH3CO2-(aq) + H3O+(l)

Chemistry
1 answer:
Evgen [1.6K]2 years ago
4 0
Correct Answer: Option C:<span> The equilibrium position will shift to the right toward the products. 

Reason:
1) This problem is based on </span>Le Chatelier's principle. It is stated as '<em>any</em><span><em> changes in the temperature, volume, or concentration of a system will result in predictable and opposing changes in the system in order minimize this change and achieve a new equilibrium state.</em>' 

2) In present case, the reaction involved is: 
</span><span>                 CH3CO2H(aq) + H2O(l) ⇄ CH3CO2-(aq) + H3O+(l) 
</span>Hence, when the concentration of acetic acid (reactant) is increased, the equilibrium will shift to right to minimize the effect of change in concentration of reactant. 
You might be interested in
Why do atoms tend to be bonded to other atoms?
Aleks04 [339]

Answer:

Atoms are often more stable when bonded to other atoms

Explanation:

Like for example let's say ionic bonds..... Since one atom has to lose specific electrons to be stable and the other needs the electrons from the other atom to be stable.....

3 0
2 years ago
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If the freezing point of the solution had been incorrectly read 0.3 °C lower than the true freezing point, would the calculated
Dovator [93]

Answer : The molar mass of the solute would be low.

Explanation :

Formula used for depression in freezing point is:  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{w_b}{M_b}\times w_a}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution

\Delta T^o = freezing point of water

i = Van't Hoff factor

K_f = freezing point constant

m = molality

w_b = mass of solute

w_a = mass of solvent

M_b = molar mass of solute

From the formula we conclude that, when the freezing point of the solution read incorrectly that is freezing point of the solution is lower than the true freezing point then this means that change in freezing point would be high and the molar mass of the solute would be low.

Hence, the molar mass of the solute would be low.

6 0
3 years ago
What is thePercent composition of dichlorine heptoxide?
Mandarinka [93]

Answer:

The percent composition of dichlorine heptoxide is 38.76% CI and 61.24% O

8 0
2 years ago
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A student compares the boiling point of substances having different intermolecular forces. which dependent variable did the stud
Gwar [14]

A student compares the boiling point of substances having different intermolecular forces. <u>Boiling points of various substances</u> is the dependent variable that student most likely use.

<h3>Does the nature of intermolecular forces present in different substance affect their boiling points?</h3>

The boiling point of a substance is proportional to the strength of its intermolecular forces, the higher the boiling point, the stronger the intermolecular forces. We can compare the strengths of intermolecular forces by comparing the boiling points of different substances.

<h3>What properties are affected by intermolecular forces?</h3>

Intermolecular forces are measured by boiling points.

Intermolecular forces increase as bond polarization increases.

Ionic > hydrogen bonding > dipole dipole > dispersion is the order of the strength of intermolecular forces (and thus their impact on boiling points).

<h3>How can you determine strong and weak intermolecular forces?</h3>

Substances with strong intermolecular forces are very attracted to one another and are held together tightly. These substances require a great deal of energy to separate, whereas substances with weak intermolecular forces are held together very loosely and have weak interactions.

Learn more about intermolecular forces:

<u><em>brainly.com/question/13479228</em></u>

#SPJ4

7 0
10 months ago
If you lived in Flagstaff, Arizona, how much salt (NaCl) would you have to add to your spaghetti water to get it to boil at 100
nasty-shy [4]

Answer:

Explanation:

This question is both theoretical and practical. While the theoretical aspect will be detailed fully here, the practical aspect will be provided as a form of guidance.

Water generally boils at 100°C when altitude (in feet) is 0. One of the colligative properties that occurs <u>when salt is added to water is that there is a boiling point elevation</u>(meaning an increase in boiling point). For instance, if 20g of salt is added to about 5.3 quarts of water, the boiling point of water will increase from 100°C to 100.04°C.

However, when the altitude/elevation of a place is about 7000 ft (like in Flagstaff, Arizona), water will boil at 95.3°C. In order to get 2 quarts of water to boil at 100°C in Flagstaff;

20g causes an increase in boiling point by 0.04°C (100°C to 100.04°C) in 5.3 quarts of water

What gram will increase the boiling point by same 0.04°C in 2 quarts

20g ⇒ 5.3

X ⇒ 2

5.3 X ⇒ 40g

X = 40 ÷ 5.3

X = 7.55g

Hence, 7.55g will cause an increase in boiling point by 0.04°C (from 100°C to 100.04°C) in 2 quarts of water

What mass of salt will increase the boiling point by 4.7°C (95.3°C to 100°C)

7.55g ⇒ 0.04

X ⇒ 4.7

X × 0.04 ⇒ 7.55 × 4.7

0.04X ⇒ 35.5

X = 887.5g

Hence, in order for the spaghetti water to boil at 100°C, 887.5g of salt needs to be added.

For the practical part of the question, some Kitchen scales have an accuracy of .25kg (250g) and some have an accuracy of .2 kg (200g) and some have an accuracy of .5kg (500g). The one your kitchen has will determine the amount of salt that you can measure. For example, if your kitchen scale/balance has an accuracy of 250g/0.25kg, then you can only measure 750g of the 887.5g (as the rest is 137.5g, which is not up to 250g of the scale's accuracy) of the required salt measurement. However, if you have a digital balance that can measure up to 2kg/2000g in one decimal place, that's the perfect balance to measure this salt.

5 0
3 years ago
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