What is the factored form of the expression?Factor completely.15g^3+18g^2-10g-12

1 answer:

8 0

Step 1: write the number as a product, helps visualizing common factors.
$3*(5g)*g^2 + (2*3)*3 g^2-2*(5g) -2*(2*3)$
I've marked things being repeating, so, group them up
$5g(3g^2-2)+6(3g^2-2)$
Now you have a common factor again
$(3g^2-2)(5g+6)$
Extra, if you want to split the first one, you can see it as the difference of $(\sqrt{3}g)^2$ and $\sqrt{2}$ which is further split into $( \sqrt{3} g+\sqrt{2}) (\sqrt{3} g-\sqrt{2})$

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30 Points! please help!

SVEN [57.7K]

Answer:

18) 4 * 10 ^ -10

19) t ^ 9

Step-by-step explanation:

18. When multiplying in scientific notation, just multiply the regular numbers together and add the exponents for the tens.

So it'll be 40 * 10^-11

However, the beginning number should have the decimal right after the 4, not any place after (for example, it's 3.056, not 30.56 or 3056.)

To fix this, move the decimal place forward one space from 40. to 4.0, and add 1 to the -11 power.

So the answer is now 4 * 10^-10

19. When dividing exponents, if the base number is the same, you can divide. (Basically, you can not divide x^2 and y^3 because x and y aren't the same)

Since in this case it's t, you can divide.

Dividing exponents is simple: just subtract them.

14 - 5 = 9

so the answer is t ^ 9

3 0

4 years ago

Create an equivalent expression that includes a set of parentheses that make the value of the expression 13. Remember, you can h

kenny6666 [7]

I don't think that you put parentheses around any numbers because when I solve it with parentheses between numbers I get other numbers like 16 or 17

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3 years ago

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