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kirza4 [7]
4 years ago
10

What is the factored form of the expression?Factor completely.15g^3+18g^2-10g-12

Mathematics
1 answer:
Komok [63]4 years ago
8 0
Step 1: write the number as a product, helps visualizing common factors.
3*(5g)*g^2 + (2*3)*3 g^2-2*(5g) -2*(2*3)
I've marked things being repeating, so, group them up
5g(3g^2-2)+6(3g^2-2)
Now you have a common factor again
(3g^2-2)(5g+6)
Extra, if you want to split the first one, you can see it as the difference of (\sqrt{3}g)^2 and \sqrt{2} which is further split into( \sqrt{3} g+\sqrt{2}) (\sqrt{3} g-\sqrt{2})
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Plz help!!!!!!!!!!!!!
pantera1 [17]

Answer:

the third one

Step-by-step explanation:

-b to start is -(-6) which is 6

needs the plus and minus

the first expression is the whole numerator

5 0
4 years ago
Read 2 more answers
In a recent study, researchers found that 31 out of 150 boys aged 7-13 were overweight or obese. On the basis of this study can
AURORKA [14]

Answer:

1) Null hypothesis:p \leq 0.15  

Alternative hypothesis:p > 0.15  

2) The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) z_{crit}= 1.64

And the rejection zone would be z>1.64

4) Calculate the statistic  

z=\frac{0.207 -0.15}{\sqrt{\frac{0.15(1-0.15)}{150}}}=1.955  

5) Statistical decision  

For this case our calculated value is on the rejection zone, so we have enough evidence to reject the null hypothesis at 5% of significance and we can conclude that the true proportion is higher than 0.15

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=21 represent the boys overweight

\hat p=\frac{31}{150}=0.207 estimated proportion of boy overweigth

p_o=0.15 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

1) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the true proportion of boys obese is higher than 0.15.:  

Null hypothesis:p \leq 0.15  

Alternative hypothesis:p > 0.15  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

2) The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Decision rule

For this case we need a value on the normal standard distribution who accumulates 0.05 of the area on the right tail and on this case this value is:

z_{crit}= 1.64

And the rejection zone would be z>1.64

4) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.207 -0.15}{\sqrt{\frac{0.15(1-0.15)}{150}}}=1.955  

5) Statistical decision  

For this case our calculated value is on the rejection zone, so we have enough evidence to reject the null hypothesis at 5% of significance and we can conclude that the true proportion is higher than 0.15

6 0
3 years ago
5x + 7 = 2x - 8 can anyone say how to solve please ​
SCORPION-xisa [38]

Answer:

x = - 5

Step-by-step explanation:

Given

5x + 7 = 2x - 8 ( subtract 2x from both sides )

3x + 7 = - 8 ( subtract 7 from both sides )

3x = - 15 ( divide both sides by 3 )

x = - 5

4 0
3 years ago
Can anyone help me ASAP!
TiliK225 [7]

Answer:

17.3 in

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A bus has less than 42 seats. If 36 seats are already occupied, write an
Fudgin [204]

Answer:

B

Step-by-step explanation:

A x - 36 <42 is wrong because its saying how many can be added

B x +36 < 42 this one is most likely correct because its displays x as how many can be added

C x - 36 > 42 this is wrong because the bus has less than 42 seats

D x + 36 >57 like i said cant be over 42

8 0
3 years ago
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