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pochemuha
3 years ago
8

Solve for C please help me if the answer is correct I will mark you as the best answer!?!!!?!!

Mathematics
2 answers:
JulsSmile [24]3 years ago
8 0

Answer:

option 1 is correct..

Hope it helps

Shkiper50 [21]3 years ago
6 0

Answer:

Option 1

Step-by-step explanation:

When you move the a2-2b to the other side of the equation, their signs change too.

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For inequalities what does at least mean
pochemuha
Greater than or equal to
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3 years ago
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9(x +1) +{2y(z -1)}/2<br> Solve for y<br><br> How do you do this? I’m confused
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Answer
If only {2y(z-1)} is being divided by two:

9x+9+yz-y

If whole equation is divided by two:

9x+9+2yz-2y over 2

Explanation: In the first instance, you can cancel out the 2 in the numerator and denominator, which leaves you 9(x+1) + {y(z-1)}. You can then simplify to get 9x+9+yz-y

In the second instance, you distribute 9 to what is inside the parentheses, and get 9x+1. You then distribute 2y to what is inside the parentheses within the brackets and get 2yz-2y. You are then left with 9x+9+2yz-2y over 2

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3 years ago
BLK = (congruent) ACK
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AAA

two alternate angle

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5 0
3 years ago
Kaylee has $0.90 worth of nickels and dimes. She has a total of 14 nickels and dimes altogether. By following the steps below, d
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Answer:

10

Step-by-step explanation:

4 0
3 years ago
Intelligence quotients​ (IQs) measured on the Stanford Revision of the Binet Simon Intelligence Scale are normally distributed w
nevsk [136]

Answer:

the percentage of people who have an IQ between 115 and 140 is 16.79%

Step-by-step explanation:

From the information given:

We are to  determine the percentage of people who have an IQ between 115 and 140.

i.e

P(115 < X < 140) = P( X  ≤ 140) - P( X  ≤ 115)

P(115 < X < 140) = P( \dfrac{X-100}{\sigma}\leq \dfrac{140-100}{16})-P( \dfrac{X-100}{\sigma}\leq \dfrac{115-100}{16})

P(115 < X < 140) = P( Z\leq \dfrac{140-100}{16})-P( Z\leq \dfrac{115-100}{16})

P(115 < X < 140) = P( Z\leq \dfrac{40}{16})-P( Z\leq \dfrac{15}{16})

P(115 < X < 140) = P( Z\leq 2.5)-P( Z\leq 0.9375)

P(115 < X < 140) = P( Z\leq 2.5)-P( Z\leq 0.938)

From Z tables :

P(115 < X < 140) = 0.9938-0.8259

P(115 < X < 140) = 0.1679

Thus; we can conclude that the percentage of people who have an IQ between 115 and 140 is 16.79%

3 0
3 years ago
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