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Marta_Voda [28]
3 years ago
10

Value of peters house has risen 20% a year for the last three years. If the value of peters home three years ago was $120 thousa

nd what is the value now
Mathematics
1 answer:
notka56 [123]3 years ago
8 0

Answer:

The value now = $207,360

Step-by-step explanation:

Rate of increase = 20% per year = 20/100 = 0.2 per year

value 3 years ago = $120,000

interest at year 1:

20% of 120,000

= 0.2 × 120,000 = 24,000

Value at the end of year 1

= initial value + interest

= 120,000 + 24,000 = $144,000

In year 2:

20% of 144,000

= 0.2 × 144,000 = 28,800

Value at the end of year 2:

144,000 + 28,800 = $172,800

In year 3

0.2 × 172,800 = 34,560

Value at the end of year 3:

34,560 + 172,800 = $207,360

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Answer:

it's d because it's correct

Step-by-step explanation:

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2 years ago
an educational psychologist wanted to know the effects of four different methods of teaching arithmetic. using 12 classrooms, ea
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What is controlled variable?

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6 0
1 year ago
How long will each person take to run a total of 50 miles at the given rates?
forsale [732]
Problema Solution

Terrance and Jesse are training for a long-distance race. Terrance trains at a rate of 6 miles every half hour, and Jesse trains at a rate of 2 miles every 15 minutes.

How long will each person take to run a total of 50 miles at the given rates?

Answer provided by our tutors

d = 50 mi the distance
t1 = the time of Terrance
t2 = the time of Jesse
Terrance trains at a rate of 6 miles every half hour thus his rate is:
v1 = 6/0.5 = 12 mph
Jesse trains at a rate of 2 miles every 15 minutes thus his rate is:
v2 = 2/(15/60) = 8 mph
since speed = distance/time follows time = distance/speed:
t1 = d/v1
t1 = 50/12
t1 = 4 1/6 hr
t1 = 4 hr 10 min
t2 = d/v2
t2 = 50/8
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Terrance will run 4 hours and 10 minutes.
Jesse will run 6 hours and 15 minutes.

6 0
3 years ago
Porfabor necesito ayuda en la esta pregunta. ¿Encuentra cuatro pares ordenados de la siguiente función? f(x) = X3 – 2X2 – 2
zlopas [31]

Answer:

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de f(x) = x^{3}-2\cdot x^{2}-2.

Step-by-step explanation:

Un par ordenado es un elemento de la forma (x,f(x)), donde x es un elemento del dominio de la función, mientras f(x) es la imagen de la función evaluada en x. Entonces, un par ordenado que está contenido en la citada función debe satisfacer la siguiente condición:

La imagen de la función existe para un elemento dado del dominio. Esto es:

x \rightarrow f(x)

Dado que f(x) es una función polinómica, existe una imagen para todo elemento x. Ahora, se eligen elementos arbitrarios del dominio para determinar sus imágenes respectivas:

x = 0

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f(0) = -2

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x = 1

f(1) = 1^{3}-2\cdot (1)^{2}-2

f(1) = -3

(1, -3) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

x = 2

f(2) = 2^{3}-2\cdot (2)^{2}-2

f(2) = -2

(2, -2) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

x = 3

f(3) = 3^{3}-2\cdot (3)^{2}-2

f(3) = 7

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Studentka2010 [4]

Step-by-step explanation:

3x+3² , you might want a second opinion I am no good at math but I tried to work it out to see if I would get it right so don't quote me on this and put it down for an answer get a second opinion please

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3 years ago
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