Which inequality has a solid boundary line when graphed?
2 answers:
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Answer:
90 pounds, 210 pounds
Step-by-step explanation:
<u>Given</u>:
A storekeeper wants to mix two types of flour to get 300 pounds, so he can sell it by 2.50$ per pound.
He uses flour worth $2.40 a pound with another flour worth $3.00 a pound.
<u>Question</u>:
How many pounds of each does he use?
Solution:
Let pounds of one type of flour mixed =
Then pounds of another type of flour mixed =
Cost of 1 pound of one type of flour = $2.40
Cost of pounds of one type of flour =
<u>Similarly</u>,
Cost of 1 pound of another type of flour = $3
Cost of pounds of another type of flour =
Cost of mixed flour per pound = $2.5
Total cost of mixed flour per pound = $2.5 300 = $750
Cost of pounds of one type + Cost of
pounds of another type = $750
Pounds of one type of flour mixed = = 90 pounds
Pounds of another type of flour mixed = = 300 - 90 = 210 pounds
Thus, 90 pounds of one and 210 pound of another type of flour mixed.
Answer:
See explanation
Step-by-step explanation:
<u>Part A:</u> If Cole eats 3 bananas each day. These 3 bananas contain mg of iron.
Let x be the number of vitamins Cole takes. Each whole vitamin contains 4 mg of iron, then x vitamins contain 4x mg of iron.
The total amount of iron Cole takes is
Cole needs to include at least 11 mg and at most 22 mg of iron in his diet each day, so
Solve it:
The smallest number of vitamins - 3, the greatest number of vitamins - 5.
<u>Part B: </u>Cole continues to eat 3 bananas each day. He pays for bananas per week.
If Cole spends a total of $20 on bananas and vitamins this week, then he spent $20 - $14 = $6 on vitamins.
Let x be the number of vitamins Cole takes this week.
First 10 vitamins are free, then x - 10 vitamins each cost $0.50 (he pays an additional dollar for every 2 additional vitamins he purchases) and they cost
This amount of money is exactly $6, so
This means Cole takes 3 vitamins per day (the whole number) and he is able to meet his iron requirement every day this week, based on answer in Part A.