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noname [10]
3 years ago
5

Suppose there is a 1.1 Fahrenheit a drop in temperature for every thousand feet that an airplane climbs into the sky and the tem

perature on the ground is 57.9 Fahrenheit what will be the temperature at the altitude of 11,000 feet
Mathematics
1 answer:
Mashutka [201]3 years ago
3 0

Answer:

45.8 degrees

Step-by-step explanation:

We know that the temp before take off is 57.9

We also know the temp decreases every 1,000 feet so

if we are 11,000 feet in the air and divide that 11000/1000=11

We know that the temp drops 11 times

11x1.1=12.1

57.9-12.1=45.8 degrees

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2 years ago
Is 690,269 divisible by 9? Yes or No?
jonny [76]

Answer:

False.

Step-by-step explanation:

It is false because when dividing an odd number by an odd number, it usually isn't divisible. In this case, 690,26<u>9</u>. Is an odd number, because the last number, 9, is odd, which makes the whole thing odd. So, odd divided by odd never turns out well. (By the way the answer is 76,696.5555556).

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What is meant mathematically when we say we have an "even" or "odd" function?
Klio2033 [76]
I a function is even the leading term will have an even exponent. If a function is odd than the leading terms exponent is odd.

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3 years ago
Do 4-11 for brainliest questions are really easy.
nasty-shy [4]

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Step-by-step explanation:

6 0
3 years ago
Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a
Vitek1552 [10]

Answer:

2ab - 6a + 5b - 15

Step-by-step explanation:

Given

2ab - 6a + 5b + \_

Required

Fill in the gap to produce the product of linear expressions

2ab - 6a + 5b + \_

Split to 2

(2ab - 6a) + (5b + \_)

Factorize the first bracket

2a(b - 3) + (5b + \_)

Represent the _ with X

2a(b - 3) + (5b + X)

Factorize the second bracket

2a(b - 3) + 5(b + \frac{X}{5})

To result in a linear expression, then the following condition must be satisfied;

b - 3 = b + \frac{X}{5}

Subtract b from both sides

b - b- 3 = b - b+ \frac{X}{5}

- 3 = \frac{X}{5}

Multiply both sides by 5

- 3 * 5 = \frac{X}{5} * 5

X = -15

Substitute -15 for X in 2a(b - 3) + 5(b + \frac{X}{5})

2a(b - 3) + 5(b + \frac{-15}{5})

2a(b - 3) + 5(b - \frac{15}{5})

2a(b - 3) + 5(b - 3)

(2a + 5)(b - 3)

The two linear expressions are (2a+ 5) and (b - 3)

Their product will result in 2ab - 6a + 5b - 15

<em>Hence, the constant is -15</em>

3 0
3 years ago
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