1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lyudmila [28]
3 years ago
9

In San Jose a sample of 73 mail carriers showed that 30 had been bitten by an animal during one week. In San Francisco in a samp

le of 80 mail carriers, 56 had received animal bites. Is there a significant difference in the proportions? Use a 0.05. Find the 95% confidence interval for the difference of the two proportions. Sellect all correct statements below based on the data given in this problem.1. -.4401 ≤ p1 - p2 ≤ -.13802. -.4401 ≤ p1 - p2 ≤ .13803. The rate of mail carriers being bitten in San Jose is statistically greater than the rate San Francisco at α = 5%4. The rate of mail carriers being bitten in San Jose is statistically less than the rate San Francisco at α = 5%5. The rate of mail carriers being bitten in San Jose and San Francisco are statistically equal at α = 5%
Mathematics
1 answer:
dsp733 years ago
8 0

Answer:

(0.411-0.7) - 1.96 \sqrt{\frac{0.411(1-0.411)}{73} +\frac{0.7(1-0.7)}{80}}=-0.4401  

(0.411-0.7) + 1.96 \sqrt{\frac{0.411(1-0.411)}{73} +\frac{0.7(1-0.7)}{80}}=-0.1380  

We are confident at 95% that the difference between the two proportions is between -0.4401 \leq p_B -p_A \leq -0.1380

1.  -.4401 ≤ p1 - p2 ≤ -.1380

4.  The rate of mail carriers being bitten in San Jose is statistically less than the rate San Francisco at α = 5%

Step-by-step explanation:

In San Jose a sample of 73 mail carriers showed that 30 had been bitten by an animal during one week. In San Francisco in a sample of 80 mail carriers, 56 had received animal bites. Is there a significant difference in the proportions? Use a 0.05. Find the 95% confidence interval for the difference of the two proportions. Sellect all correct statements below based on the data given in this problem.

1.  -.4401 ≤ p1 - p2 ≤ -.1380

2.  -.4401 ≤ p1 - p2 ≤ .1380

3.  The rate of mail carriers being bitten in San Jose is statistically greater than the rate San Francisco at α = 5%

4.  The rate of mail carriers being bitten in San Jose is statistically less than the rate San Francisco at α = 5%

5.  The rate of mail carriers being bitten in San Jose and San Francisco are statistically equal at α = 5%

Solution to the problem

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p_1 represent the real population proportion for San Jose

\hat p_1 =\frac{30}{73}=0.411 represent the estimated proportion for San Jos

n_1=73 is the sample size required for San Jose

p_2 represent the real population proportion for San Francisco

\hat p_2 =\frac{56}{80}=0.7 represent the estimated proportion for San Francisco

n_2=80 is the sample size required for San Francisco

z represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_1 -\hat p_1) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

And replacing into the confidence interval formula we got:  

(0.411-0.7) - 1.96 \sqrt{\frac{0.411(1-0.411)}{73} +\frac{0.7(1-0.7)}{80}}=-0.4401  

(0.411-0.7) + 1.96 \sqrt{\frac{0.411(1-0.411)}{73} +\frac{0.7(1-0.7)}{80}}=-0.1380  

We are confident at 95% that the difference between the two proportions is between -0.4401 \leq p_B -p_A \leq -0.1380

Since the confidence interval contains all negative values we can conclude that the proportion for San Jose is significantly lower than the proportion for San Francisco at 5% level.

Based on this the correct options are:

1.  -.4401 ≤ p1 - p2 ≤ -.1380

4.  The rate of mail carriers being bitten in San Jose is statistically less than the rate San Francisco at α = 5%

You might be interested in
If the length of each side of an equilateral triangle were increased by 50 percent, what would be the percent increase in the ar
Shkiper50 [21]

Answer:

<u><em>The area increase by 225%</em></u>

<em><u>Step-by-step explanation: </u></em>

<em><u>attachment of a triangle</u></em>

<em><u>The area of a triangle equilateral is calculated with the next formula:</u></em>

<em><u>A=\frac{a*h}{2}</u></em>

<em><u>h^{2} +(\frac{a}{2})^{2}=a^{2}</u></em>

<em><u>h^{2} = a^{2} - \frac{a^{2} }{4}= \frac{a^{2} }{4}*3</u></em>

<em><u>h=\sqrt{\frac{a^{2}*3 }{4} }</u></em>

<em><u>h=\frac{\sqrt{3}*a }{2}</u></em>

<em><u>replacing in the A equation:</u></em>

<em><u>A=\frac{a*\sqrt{3}*a }{2*2}</u></em>

<em><u>A=\frac{\sqrt{3}*a^{2} }{4}</u></em>

<em><u>Now each side increse by 50% ⇒ a=1.5a</u></em>

<em><u>A= \frac{\sqrt{3}*(1.5a)^{2} }{4}</u></em>

<em><u>A=\frac{\sqrt{3}*a^{2}* 2.25 }{4}</u></em>

<em><u>A=2.25 * \frac{\sqrt{3}*a^{2} }{4}</u></em>

<em><u>It means that the area incrase by 225%</u></em>

6 0
3 years ago
Find the mean median mode and range 2,5,9,4,3
snow_lady [41]
Mean: 4.6 (basically the average
Median: 4 (the number in the middle
Mode: there isn’t one (it’s the number repeated the most)
Range: 7 (largest and smallest number subtracted
3 0
3 years ago
Read 2 more answers
Solve the quadratic equations below using the factorization method.
liubo4ka [24]

Answer: omg this is hard

Step-by-step explanation:

4 0
3 years ago
Need some funny hair jokes for math teacher plss​
Fiesta28 [93]

Answer:

Grey Hairs? Try some of our free Pi-Lights

Step-by-step explanation:

4 0
3 years ago
What are the coefficients for the binomial expansion of (p+q)^6
seropon [69]

Answer:

1 6 15 20 15 6 1

Step-by-step explanation:

To figure this out, we need to look at Pascal's Triangle, which is a tricky little way to find the coefficients for any binomial expression like this! Check the attached photo.

Because this is to the sixth, we need the 6th row, which is <u>1 6 15 20 15 6 1.</u> From this, we know that those numbers are the coefficients!

8 0
3 years ago
Read 2 more answers
Other questions:
  • What is 346% as a fraction
    12·2 answers
  • Find the value of x and y.<br>I haven't learned this yet and I really need help ​
    11·1 answer
  • Anyone know the answer
    8·2 answers
  • Which graph represents the solution to the system of inequalities?
    7·2 answers
  • -x + 2y = 21<br> 5x + 6y = 23
    5·2 answers
  • You are offered two stocks. The beta of A is 1.4 while the beta of B is 0.8. The growth rates of earnings and dividends are 10%
    12·1 answer
  • Helppppppppppppppppppppppp
    5·1 answer
  • suppose the expression was (12-3) to the second power would you have to still simplify 3 to the second power first explain
    14·1 answer
  • The art club had an election to select president​
    15·1 answer
  • The ratio of the sides of a triangle is 2:4:9. If the perimeter is 165 inches, what is the length of the longest side?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!